Answer:
1.07 ×10² j/g.°C
Explanation:
Given data:
Mass of substance Z = 13.5 g
Amount of heat absorbed = 36 Kj (36×1000 = 36000 j)
Increase in temperature= ΔT = 25°C
Specific heat of substance = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Now we will put the values in formula.
Q = m.c. ΔT
36000 j = 13.5 g ×c×25°C
36000 j / 13.5 g×25°C = c
c = 36000 j /337.5 g.°C
c = 1.07 ×10² j/g.°C
Electrons allow for chemical bonds to form.
Answer:
The temperature at which the vapor pressure of a liquid is just equal to the external ... The conversion of a liquid to a gas below the boiling point is called ... equilibrium temperature of the mixture was 36.0 °C. What is the specific heat (J/ g°C) of the metal
Explanation:
Answer:
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Explanation:
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