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mr Goodwill [35]
3 years ago
13

N2-3H2 → 2NH3

Chemistry
1 answer:
aniked [119]3 years ago
8 0

Answer:

6 mols H2 are needed

Explanation:

N2 = 28.01g/mol

H2 = 2.02g/mol

\frac{2 mol N_{2} }{1} * \frac{3 mol H_{2}  }{ 1 mol N_{2} } = 6 mol H2

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What is the empirical formula for a compound that is 29.44\% calcium, 23.55% sulfur, and 47.01% oxygen? This compound is a commo
PSYCHO15rus [73]

Answer:

Empirical formula is CaSO₄.

Explanation:

Given data:

Percentage of calcium =29.44%

Percentage of sulfur = 23.55%

Percentage of oxygen = 47.01%

Empirical formula = ?

Solution:

Number of gram atoms of Ca = 29.44 / 40 = 0.74

Number of gram atoms of S = 23.55 / 32 = 0.74

Number of gram atoms of O = 47.01 / 16 = 3

Atomic ratio:

            Ca                      :        S                :         O

           0.74/0.74           :     0.74/0.74      :       3/0.74

               1                     :          1              :          4

Ca : S : O = 1 : 1 : 4

Empirical formula is CaSO₄.

3 0
3 years ago
The production of iron and carbon dioxide from iron(iii) oxide and carbon monoxide is an exothermic reaction. which expression c
NARA [144]
Missing question:
A. [3.40 mol Fe2O3 (s) × 26.3 kJ/1 mol Fe2O3 (s)] / 2 
<span>B. 3.40 mol Fe2O3 (s) × 26.3 kJ/1 mol Fe2O3 (s) </span>
<span>C. 26.3 kJ/1 mol Fe2O3 (s) / 3.40 mol Fe2O3 (s) </span>
<span>D. 26.3 kJ/1 mol Fe2O3 (s) – 3.40 mol Fe2O3 (s).
</span>Answer is: B.
Chemical reaction: F<span>e</span>₂O₃<span>(s) + 3CO(g) → 2Fe(s) + 3CO</span>₂<span>(g);</span>ΔH = <span>+ 26.3 kJ.
When one mole of iron(III) oxide reacts 26,3 kJ of energy is required and for 3,2 moles of iron(III) oxide 3,2 times more energy is required.</span>
8 0
3 years ago
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2 grams of a substance was dissolved in 75.0 g of water resulting in a temperature decrease from 23.1 ⁰C to 18.7 ⁰C. The specifi
RUDIKE [14]
<h3>Answer:</h3>

1379.4 Joules

<h3>Explanation:</h3>
  • The quantity of heat is calculated multiplying the mass of a substance by heat capacity and the change in temperature.

Therefore;

Quantity of heat = Mass × specific heat capacity × Change in temperature

Q = mcΔT

In this case;

The substance dissolved in water gained heat while water lost heat energy.

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Heat associated with the water  

Mass of water = 75 g

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Specific heat capacity =  4.18 J/g·⁰C

Heat = mcΔT

        = 75 g × 4.18 J/g·⁰C × 4.4 °C

        =1379.4 Joules

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