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3 years ago

N2-3H2 → 2NH3

Chemistry

1 answer:

aniked [119]3 years ago

8 0

Answer:

6 mols H2 are needed

Explanation:

N2 = 28.01g/mol

H2 = 2.02g/mol

$\frac{2 mol N_{2} }{1}$ * $\frac{3 mol H_{2} }{ 1 mol N_{2} }$ = 6 mol H2

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Which agent of erosion can create a limestone cave?

Ivanshal [37]

Water containing carbonic acid and calcium

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3 years ago

Which statement describes both homogeneous mixtures and heterogeneous mixtures?

stiks02 [169]

Answer:

both are the types of mixture and both are impure substances that donot have fixed composition and the composition of constituents is not uniform

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3 years ago

The entropy change for a real, irreversible process is equal to:______.

taurus [48]

Answer:

The entropy change for a real, irreversible process is equal to zero.

The correct option is 'c'.

Explanation:

Lets look around all the given options -:

(a) the entropy change for a theoretical reversible process with the same initial and final states , since the entropy change is equal and opposite in reversible process , thus this option in not correct.

(b) equal to the entropy change for the same process performed reversibly ONLY if the process can be reversed at all. Since , the change is same as well as opposite too . Therefore , this statement is also not true .

(c) zero. This option is true because We generate more entropy in an irreversible process. Because no heat moves into or out of the surroundings during the procedure, the entropy change of the surroundings is zero.

(d) impossible to tell. This option is invalid , thus incorrect .

Hence , the correct option is 'c' that is zero.

8 0

3 years ago

What mass of iron is needed to react with sulfur in order to produce 96 grams of

fiasKO [112]

Answer:

51.69 g of Fe

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2Fe + 3S —> Fe₂S₃

Next, we shall determine the mass of Fe that reacted and the mass of Fe₂S₃ produced from the balanced equation. This can be obtained as follow:

Molar mass of Fe = 56 g/mol

Mass of Fe from the balanced equation = 2 × 56 = 112 g

Molar mass of Fe₂S₃ = (2×56) + (3×32)

= 112 + 96

= 208 g/mol

Mass of Fe₂S₃ from the balanced equation = 1 × 208 = 208 g

SUMMARY:

From the balanced equation above,

112 g of Fe reacted to produce 208 g of Fe₂S₃.

Finally, we shall determine the mass of Fe needed to produce 96 g of Fe₂S₃. This can be obtained as follow:

From the balanced equation above,

112 g of Fe reacted to produce 208 g of Fe₂S₃.

Therefore, Xg of Fe will react to produce 96 g of Fe₂S₃ i.e

Xg of Fe = (112 × 96)/208

Xg of Fe = 51.69 g

Thus, 51.69 g of Fe is needed for the reaction.

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3 years ago

How many moles of nitrogen monoxide will be generated when 0.83 moles of nitrogen dioxide gas reacts with water? 3NO2 + H2O 2HNO

statuscvo [17]

3NO₂ + H₂O→2HNO₃ + NO

n(NO)=n(NO₂)/3

n(NO)=0.83/3=0.277 mol

4 0

3 years ago

Read 2 more answers