It isn't balanced. You have 3 *H and 3 * O, so something in the first formula must be changed. Have been searching for 1 hour and can't find the answer.
Answer:
(1) Nonbonding electron pairs are present on the F in the molecule HF. True
(2) The two atoms involved in a multiple covalent bond must always be atoms of the same element. False
(3) A molecule of hydrogen peroxide contains the same number of atoms as a molecule of sulfur trioxide does. True
Two of the three statements are true.
Explanation:
Non bonding electrons are also known as lone pairs. They are electron pairs present on an atom but are not involved in chemical bonding. They are usually localized on the atom of one of the bonding elements. In HF, there are three nonbonding electrons localized on the fluorine atom that do not participate in chemical bonding.
When multiple bonds are formed between atoms, they must not be atoms of the same element, for instance carbon and nitrogen forms multiple covalent bonds in chemical moieties such as they cyanide ion.
A molecule of hydrogen peroxide (H2O2) contains four atoms just as a molecule of sulphur trioxide(SO3) does.
Answer: 724.71 grams
Explanation:
Volume of solution (v) = 5.1 liters
Concentration of solution (c) = 1.4M
Amount of CuF2 needed (n) = ?
Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence
c = n / v
make n the subject formula
n = c x v
n = 1.4M x 5.1 Liters
n = 7.14 moles
Since, 7.14 moles of CuF2 (n) is needed, use the molar mass of CuF2 to get the mass in grams.
The atomic masses of Copper = 63.5g;
and Fluorine = 19g
So, I CuF2 = 63.5g + (19g x 2)
= 63.5g + 38g
= 101.5g/mol
Then, apply the formula
Number of moles = mass in grams / molar mass
7.14 moles = m / 101.5 g/mol
m = 7.14 moles x 101.5 g/mol
m = 724.71g
Thus, 724.71 grams of copper (II) fluoride, CuF2, are needed to make 5.1 liters of a 1.4M solution
Explanation:
It is known that relation between 
, 
, and pH is as follows.
![E_{cell} = E^{o}_{cell} - (\frac{0.0591}{n}) \times log[H^{+}] ](https://tex.z-dn.net/?f=E_%7Bcell%7D%20%3D%20E%5E%7Bo%7D_%7Bcell%7D%20-%20%28%5Cfrac%7B0.0591%7D%7Bn%7D%29%20%5Ctimes%20log%5BH%5E%7B%2B%7D%5D%0A)
Also, it is known that for hydrogen is equal to zero.
Hence, substituting the given values into the above equation as follows.
0.238 V = 0 - (\frac{0.0591}{1}) \times log[H^{+}]
[/tex]
![-log[H^{+}]](https://tex.z-dn.net/?f=-log%5BH%5E%7B%2B%7D%5D)
= 4.03
![[H^{+}]](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D)
= antilog 4.03
= 3.5
As, pH = .
Thus, we can conclude that pH of the given unknown solution at 298 K is 3.5.
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