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Kitty [74]
3 years ago
5

PLEASE HELP PLEASE PLEASE

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
4 0

Answer: The value of x =2 units.

Explanation:

Since we have given that

AD= CD

BE= EA

So, we get that D and E are the mid-points of AC and AB respectively.

So, by Mid- point theorem , which states that the line joining the two midpoints is parallel to third side and it is half in length of third side i.e.

DE=\frac{1}{2}BC

So, we put the value of DE  and BC ,

5x-3=\frac{1}{2}\times (x+12)\\\\2(5x-3)=x+12\\\\10x-6=x+12\\\\10x-x=12+6\\\\9x=18\\\\x=\frac{18}{9}=2

Hence, the value of x =2 units.


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Miranda has 4 lb 6 oz of clay is she divided it into 10 equal parts how heavy is each part?
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Each part would be 20z of Clay
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3 years ago
The sum of two numbers is 100 and their difference is -20. What are the two numbers?
salantis [7]

Answer:

x=40 and y= 60

Step-by-step explanation:

<u>step:1</u>

Let 'x' and 'y' are two numbers

given data the sum of two numbers is 100

x+y = 100......(1)

Given difference of two numbers are

x - y = -20 ......(2)

<u>Step :2</u>

solving the equation (1) and (2)

adding the equations (1) and (2)

x+y+x-y=100-20

cancelling 'y' terms are

2 x = 80

dividing "2" on both sides, we get

x = 40

<u>Step :3</u>

substitute x = 40 in equation (1)

x + y =100

40 + y = 100

subtracting "40" on both sides, we get

40 + y - 40 = 100 -40

y = 60

Final answer:-

The two numbers are x = 40 and y= 60

3 0
3 years ago
Hey umm how do you make your stressed mom feel better?
Dafna11 [192]

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Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Prove that :-<br><br> Cos3A-cosA/sin3A-sinA+cos2A-cos4A/sin4A-sin2A=sinA/cos2Acos3A
ad-work [718]
\dfrac{\cos^3A-\cos A}{\sin^3A-\sin A}+\dfrac{\cos^2A-\cos^4A}{\sin^4A-\sin^2A}=\dfrac{\sin A}{\cos^2A\cos^3A}\\\\L_s=\dfrac{\cos A(\cos^2A-1)}{\sin A(\sin^2A-1)}+\dfrac{\cos^2A(1-\cos^2A)}{\sin^2A(\sin^2A-1)}\\\\=\dfrac{\cos A(-\sin^2A)}{\sin A(-\cos^2A)}+\dfrac{\cos^2A\sin^2A}{\sin^2A(-\cos^2A)}\\\\=\dfrac{\sin A}{\cos A}-1=\tan A-1

R_s=\dfrac{\sin A}{\cos A\cos^4A}=\dfrac{\sin A}{\cos A}\cdot\dfrac{1}{\cos^4A}=\tan A\cdot\dfrac{1}{\cos^4A}=\dfrac{\tan A}{\cos^4A}


\boxed{L_s\neq R_s}
8 0
2 years ago
Help me please!!!!!!!
Sav [38]

Answer:

- sign between 9 and 64 under root, it should be + sign

Step-by-step explanation:

(-4)*(-8)(2)= 64

It should read x= √9+64 but not √9-54 which lead to incorrect solution

3 0
3 years ago
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