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cluponka [151]
3 years ago
5

PLEASE HELP WITH NUMBER 11 ASAP!!!! (Please show how you got the answer)

Mathematics
1 answer:
Alex777 [14]3 years ago
7 0

Answer:

Triangle B is right

Step-by-step explanation:

Using the converse theorem of Pythagoras.

If the square of the longest side in a triangle equals the sum of the squares of the other 2 sides then the triangle is right.

Triangle A

longest side squared = 36² = 1296

26² + 18² = 676 + 324 = 1000 ≠ 1296

Hence triangle A is not right

Triangle B

longest side squared = 25² = 625

20² + 15² = 400 + 225 = 625 ← correct

Hence triangle B is right


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Which equation is rewritten in vertex form?
Zinaida [17]
(x + 3)^2 + (x + 4)^2 
= x^2 + 6x + 9 + x^2 + 8x + 16
= 2x^2 + 14x + 25
= 2(x^2 + 7x) + 25
= 2[(x + 7/2)^2  - 49/4] + 25
= 2(x + 7/2)^2 - 98/4 + 25
= 2(x + 7/2)^2 + 1/2


Its B

7 0
2 years ago
What is this math problem???<br><br> g(x)=1/20x(x-100)
Fudgin [204]

Answer:

the x intercept is (0,100) and the y intercept is (0,0)

Step-by-step explanation:

g(x)=1/20x(x-100)

g(0)=1/20(0)(0-100)

g(0)=1/20*0(0-100)

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6 0
3 years ago
Combine and simplify the following radical expression <br><br> ASAP ASAP ASAP ASAP
Montano1993 [528]

Answer:

\sqrt[3]{3}

Step-by-step explanation:

Our expression is: \frac{1}{3} \sqrt[3]{81}.

Let's focus on the cube root of 81 first. What's the prime factorisation of 81? It's simply: 3 * 3 * 3 * 3, or 3^3*3. Put this in for 81:

\sqrt[3]{81} =\sqrt[3]{3^3*3}=\sqrt[3]{3^3} *\sqrt[3]{3}

We know that the cube root of 3 cubed will cancel out to become 3, but the cube root of 3 cannot be further simplified, so we keep that. Our outcome is then:

\sqrt[3]{3^3} *\sqrt[3]{3}=3\sqrt[3]{3}

Now, let's multiply this by 1/3, as shown in the original problem:

\frac{1}{3}* 3\sqrt[3]{3}=\sqrt[3]{3}

Thus, the answer is \sqrt[3]{3}.

<em>~ an aesthetics lover</em>

6 0
3 years ago
Helpppp pleaseeeeeeee
Katena32 [7]
The answer is B) multiply 3 by 3. With that 2 on top, that doesn't mean 3 times 2, that means multiply 3 by itself, however many times the number says, if that makes sense. So if there's a 2 above the 3, then that would be 3*3. If it was a 5 instead of a two, that would mean 3*3*3*3*3. Not 3*5.
3 0
3 years ago
Always, sometimes, or never true
Kitty [74]
I think it’s always because the absolute value is always positive.
8 0
3 years ago
Read 2 more answers
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