The function of the object height is an illustration of a projectile motion
The object will never hit the ground
<h3>How to determine when the object hits the ground?</h3>
The function is given as:
h=16t^2+80t+96.
When the object hits the ground, h = 0
So, we have:
16t^2+80t+96 = 0
Divide through by 16
t^2+5t+6 = 0
Expand
t^2 + 3t + 2t + 6 = 0
Factorize
t(t + 3) + 2(t + 3) = 0
Factor out t + 3
(t + 2)(t + 3) = 0
Solve for t
t = -2 or t = -3
The time (t) cannot be negative.
Hence, the object will never hit the ground
Read more about projectile motion at:
brainly.com/question/1130127
Answer:
(3,3)
Step-by-step explanation:
Given
Required
Determine which can't be any of the new vertices
First, we need to determine the new vertices:
For (0,0):
For (1,0):
For (0,1):
<em>Comparing the calculated new vertices to the list of given options; (3,3) can't be any of the new vertices of the new triangle</em>
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H(10) is the altitude of a hot air balloon overtime after 10 minutes. In order to find h(10)'s value, you just have to substitute 10 as t in the equation. h(10) and h(t) represents the value of y in a linear equation. So pretty much: h(10)= 210 - 15(10). If calculated correctly, h(10)=60.
Answer:
the domain of a v-shaped graph is set of all real numbers
Step-by-step explanation:
