The length of the wire is the length of the hypotenuse of a triangle with one leg 60 inches and the other leg 8*4 in = 32 inches.
√(60² +32²) = √4624 = 68
The wire is 68 inches long.
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Consider what happens if you wrap a paper triangle of those dimensions around the pipe. The hypotenuse edge traces the path of the wire.
Answer:
=(a-b)(a^2+ab+b^2)
= a^3+a^2b+ab+ab^2-ba^2-ab^2-b^3
SIMPLIFY
=a^3+ab-b^3
(x - 4)^2 , i hope this helps
