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4 years ago

10 POINTS HELP!!!

Mathematics

1 answer:

nignag [31]4 years ago

3 0

Answer:The distance between the endpoints (11,−4) and (−12,−4) are 23 units

Step-by-step explanation:

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Please need help asap!

beks73 [17]

Answer:

Step-by-step explanation:

(z-33)/z = 1/2

2z-66=z

z=66

6 0

3 years ago

15 of 20 answer

expeople1 [14]

Answer:

8 bags

Step-by-step explanation:

You divided them by 20 which gives you 4. So you take the 3 and multiply by 4 which is 12 bags. And then you do the same for your bags which makes you do 2 times 4 which gives you 8. You take 20 - 12 and that leaves you with 8.

3 0

3 years ago

The Wilson family had 5 children. Assuming that the probability of a child being a girl is 0.5, find the probability that the Wi

Dafna11 [192]

Answer:

0.813

0.500

Step-by-step explanation:

Use binomial probability.

P = nCr p^r q^(n−r)

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

In this problem, n = 5, p = 0.5, and q = 0.5.

"At least 2 girls" means r = 2, 3, 4, or 5.

Or, we can use the complement.

P(at least 2 girls) = 1 − P(at most 1 girl)

P(at least 2 girls) = 1 − P(r=0 or r=1)

P(at least 2 girls) = 1 − ₅C₁ (0.5)¹ (0.5)⁵⁻¹ − ₅C₀ (0.5)⁰ (0.5)⁵⁻⁰

P(at least 2 girls) = 1 − 5 (0.5) (0.5)⁴ − 1 (1) (0.5)⁵

P(at least 2 girls) = 1 − 6 (0.5)⁵

P(at least 2 girls) ≈ 0.813

"At most 2 girls" means r = 0, 1, or 2.

P(at most 2 girls) = P(r=0, r=1, or r=2)

P(at most 2 girls) = ₅C₀ (0.5)⁰ (0.5)⁵⁻⁰ + ₅C₁ (0.5)¹ (0.5)⁵⁻¹ + ₅C₂ (0.5)² (0.5)⁵⁻²

P(at most 2 girls) = 1 (1) (0.5)⁵ + 5 (0.5) (0.5)⁴ + 10 (0.5)² (0.5)³

P(at most 2 girls) = 16 (0.5)⁵

P(at most 2 girls) = 0.500

4 0

3 years ago

A simple random sample of 50 items from a population with 7 resulted in a sample mean of 35.

Vilka [71]

The 90% , 99% confidence interval for the population mean is 32.145 < $\rm \mu$ < 35.855 and 31.093 < $\rm \mu$ < 36.907

<h3>What is Probability ?</h3>

Probability is the study of likeliness of an event to happen.

It is given that

Total Population = 50

Mean = 35

The confidence interval is given by

$\rm CI = \mu + z \dfrac{s}{\sqrt n}$

$\rm \mu$ is the mean

z is the confidence level value

s is the standard deviation

n is the population width

(a) The 90% confidence interval for the population mean

90% $\rm \alpha / 2$ = 0.05

Z = 1.64

34 $\rm \pm$ 1.64 * 8 / √50

34 $\rm \pm$ 1.855

32.145 < $\rm \mu$ < 35.855

(b) The 99% confidence interval for the population mean

99% $\rm \alpha / 2$ = 0.005

Z=2.57

34 $\rm \pm$ 2.57 * 8 / √50

34 $\rm \pm$ 2.907

31.093 < $\rm \mu$ < 36.907

Therefore the confidence interval for population mean has been determined.

The complete question is

A simple random sample of 50 items from a population width =7 resulted in a sample mean of 35. If required, round your answers to two decimal places.

a. Provide a 90% confidence interval for the population mean

b. Provide a 99% confidence interval for the population mean

To know more about Probability

brainly.com/question/11234923

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8 0

2 years ago

Gina sells 216 cakes in the ratio small :medium:large 5:7:12. The profit for one medium cake is twice the profit for one small c

Rus_ich [418]

To answer this question you need to first set up the small, medium, large number of cakes as a ratio with a total. From here you will create a new ratio of the correct number of small medium and large Cakes sold using the total 216. The factor would be to multiply by nine. -Step 1 in picture. After this you would read what the relationship is between a medium and a small and the large and the small profits are - Step 2 in picture. After this you would represents the total profit based on the number of small medium and large cakes that were sold. Making this equal to L648.45. To find the profit for one small, you would then divide 648.45 by the 495 you got when you simplify the expression. The answer is L1.31.

5 0

3 years ago

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