Velocity of the ring wraiths relative to the air:
The speed 
is what we want to find - this is the speed at which the wraiths are flying in the air.
(Note: 
denotes velocity, while 
denotes speed)
Velocity of air relative to the ground:
The ring wraiths want their trajectory to be due north, which means their velocity relative to the ground should be
To an observer on the ground, 
is the speed at which the wraiths would appear to be moving in the air.
The relative velocities satisify
Answer: - 235
<u>Step-by-step explanation:</u>
f(x) = -3x² + 13x + 3
f(-7) = -3(-7)² + 13(-7) + 3
= -3(49) - 91 + 3
= -147 - 88
= -235
Well you would first add 5/13 and 2/13, so 7/13. Then you would subtract 7 from 13. So your answer would be 6/13. Hope that helped!
2x + 2y=132
xy=1080
Let x=1080/y
2160/y + 2y=132
2y^2 - 132y +2160=0
2(y^2-66y+1080)=0
2(y-30)(y-33)=0
y=30 or y=33
(36,30) or (30,36)
So... x=30,36 and y=36,30. Either way, the answer is 30 by 36 or 36 by 30.
