In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.
To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9
To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum). The probability is 11/36
Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.
P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9
How do you want this solved?
Answer:
1 solution, 0
Step-by-step explanation:
In algebra, a variable can be equal to any amount of numbers depending on how it is used. In this case, m is only equal to the one value of 8, and therefore only has <u>one solution.</u>
m - 8
(8) - 8
0
Answer:
Measure number 2 of the tape is for the pinus
Step-by-step explanation:
To measure, kindly place pinus next to ruler and pinus will be in line with measurement #2
Call and ask for pinus step by step
