I would do this by first listing the multiples of 6 until I start to see a pattern with the one's digit.
6x0=0
6x1=6
6x2=12
6x3=18
6x4=24
6x5=30
6x6=36
6x7=42
6x8=48
...
The digits in bold are the one's digits so those are the only ones we really care about. If you list just them it looks like: 0,6,2,8,4,0,6,2,8
Notice how the first set of 5 numbers seems as though it repeats in the 6th, 7th, and 8th numbers. This probably means the pattern continues infinitely so the first 5 numbers are all the one's digits that can come from multiples of 6. Thus your answer is: 0,6,2,8,or 4
Answer:
c. 44,950,000
Step-by-step explanation:
The following table is missing:
Year Attendance (millions)
1985 18.4
1990 25.2
1995 33.1
2000 37.6
Using a calculator, the line of best fit is obtained. Equation:
y = 1.31x - 2581.6
where y is attendance (in millions) and <em>x</em> is the year. Replacing with x = 2005 into the equation, we get:
y = 1.31(2005) - 2581.6
y = 44.95 millions or 44,950,000
Given:
Atul has 
lb of candy.
Jose has 
lb of candy.
Maria has 
lb less than Jose.
To find:
How many more pounds of candy does Atul have than Maria?
Solution:
Since, Maria has lb less than Jose, therefore
Maria has = 
lb
Maria has = 
lb
Maria has = 
lb
Difference between the candies Atul and Maria have.
Difference = 
lb
Difference = 
lb
Difference = 
lb
Therefore, Atul have lb of candy more than Maria.
Answer:
Step-by-step explanation:
11/8 as a decimal... 1.375
5/9 as a decimal... 0.55555556
