Answer:
The area of the sector is 9.43 ft^2
Step-by-step explanation:
Here, we want to find the area of the sector with a central angle of 30 degrees
To do this, we use the formula below;
Area of sector = theta/360 * pi * r^2
theta = central angle = 30 degrees
r = radius = 6 ft
Thus, we have it that;
Area of sector = 30/360 * pi * 6^2
= 30/10 * pi = 3 * 3.142 = 9.43 ft^2
15 is equal to x divided by 3 plus 7
Answer:
Step-by-step explanation:
A. Directrix: y = 4-6 = -2
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B. Axis of symmetry: x = 6
Axis of symmetry intersects directrix at (6,-2)
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C . Vertex is halfway between focus and directrix, at (6,1)
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D. The focus lies above the directrix, so the parabola opens upwards.
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E. Focal length p = 1/(4×0.5)
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F. p = 0.5
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G. y = 0.5(x-6)² + 1
Answer:
The rectangular coordinates of the point are (3/2 , √3/2)
Step-by-step explanation:
* Lets study how to change from polar form to rectangular coordinates
- To convert from polar form (r , Ф) to rectangular coordinates (x , y)
use these rules
# x = r cos Ф
# y = r sin Ф
* Now lets solve the problem
∵ The point in the rectangular coordinates is (√3 , π/6)
∴ r = √3 and Ф = π/6
- Lets find the x-coordinates
∵ x = r cos Ф
∵ r = √3
∵ Ф = π/6
∴ x = √3 cos π/6
∵ cos π/6 = √3/2
∴ x = √3 (√3/2) = 3/2
* The x-coordinate of the point is 3/2
- Lets find the y-coordinates
∵ y = r sin Ф
∵ r = √3
∵ Ф = π/6
∴ y = √3 sin π/6
∵ sin π/6 = 1/2
∴ y = √3 (1/2) = √3/2
* The y-coordinate of the point is √3/2
∴ The rectangular coordinates of the point are (3/2 , √3/2)
