The combination shows that the different groups of three that can be chosen for a newspaper photo is 10.
<h3>How to calculate the value?</h3>
From the information, Joyce, Karen and Paula are starters on their school basketball team.
The information is to illustrate the different groups of three that can be chosen for a newspaper photo.
This will be:
= 5!/3!(5 - 3)!
= 5!/3!2!
= (5 × 4 × 3 × 2 × 1)/(3 × 2 × 2)
= 20/2
= 10
There will be 10 groups.
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<h3>Answer: Choice C</h3>
RootIndex 12 StartRoot 8 EndRoot Superscript x
12th root of 8^x = (12th root of 8)^x
![\sqrt[12]{8^{x}} = \left(\sqrt[12]{8}\right)^{x}](https://tex.z-dn.net/?f=%5Csqrt%5B12%5D%7B8%5E%7Bx%7D%7D%20%3D%20%5Cleft%28%5Csqrt%5B12%5D%7B8%7D%5Cright%29%5E%7Bx%7D)
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Explanation:
The general rule is
![\sqrt[n]{x} = x^{1/n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%3D%20x%5E%7B1%2Fn%7D)
so any nth root is the same as having a fractional exponent 1/n.
Using that rule we can say the cube root of 8 is equivalent to 8^(1/3)
![\sqrt[3]{8} = 8^{1/3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%20%3D%208%5E%7B1%2F3%7D)
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Raising this to the power of (1/4)x will have us multiply the exponents of 1/3 and (1/4)x like so
(1/3)*(1/4)x = (1/12)x
In other words,


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From here, we rewrite the fractional exponent 1/12 as a 12th root. which leads us to this
![8^{(1/12)x} = \sqrt[12]{8^{x}}](https://tex.z-dn.net/?f=8%5E%7B%281%2F12%29x%7D%20%3D%20%5Csqrt%5B12%5D%7B8%5E%7Bx%7D%7D%20)
![8^{(1/12)x} = \left(\sqrt[12]{8}\right)^{x}](https://tex.z-dn.net/?f=8%5E%7B%281%2F12%29x%7D%20%3D%20%5Cleft%28%5Csqrt%5B12%5D%7B8%7D%5Cright%29%5E%7Bx%7D%20)
Answer:
I ha.te U bit.ch
Step-by-step explanation:
Also, do U like these images?
Step-by-step explanation:
Part A
A) The denominator is 665, so this is a terminating decimal.
B) 11/99 = 1/9 = 0.1111...
C) 256/999 = 0.256256256...
D) 25/909 = 275/9999 = 0.027502750275...
B has 1 repeating digit, C has 3 repeating digits, and D has 4 repeating digits. So the correct answer is C.
Part B
A decimal that can be written as a ratio of integers is a rational number.
Recursive equation would be f(x+1) = f(x) - 25 with f(0) = 300
Explicit equation would be f(x) = -25x + 300
And graph would looks like this: