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8090 [49]
3 years ago
11

Who knows what is the answer?

Mathematics
1 answer:
stich3 [128]3 years ago
3 0
Set x=10 as equation 1 and 3x+5y=20 as equation 2

x=10----------(1)
3x+5y=20-----------(2)

substitute (1) into (2),
3(10)+5y=20
30+5y=20
30–20=–5y
10=–5y
5y=–10
y=–10÷5
y=–2

final ans:(10,–2)

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