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o-na [289]
3 years ago
9

I WILL MARK BRAINLIST!!

Mathematics
2 answers:
olga55 [171]3 years ago
7 0

Answer:

2x2 + 8x − 8; will be a polynomial

Step-by-step explanation:

Soloha48 [4]3 years ago
3 0

Answer:

For (2x^2 + 8x - 8), the group is CLOSED as it a polynomial.

Step-by-step explanation:

Here, the given polynomials are:

P(x)=(5x^2+2x-6)\\Q(x)=(3x^2-6x+2)

Now, a group G is said to be <u>CLOSED UNDER SUBTRACTION</u> if,

a and b are he elements of G ⇒ (a-b) is ALSO AN ELEMENT of G

Now, here:

R(x)  = P(x) - Q(x) = (5x^2+2x-6) - (3x^2-6x+2) = (2x^2 + 8x - 8)

or, R(x)  = (2x^2 + 8x - 8)

Also, R(x) is a POLYNOMIAL.

So, R(x) is an Element of group G.

So, the set G of polynomials.

Hence, for the polynomial  (2x^2 + 8x - 8), it will be a polynomial the group is CLOSED.

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Can somebody prove this mathmatical induction?
Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

\sum \limits_{j=1}^k2^j=2(2^k-1)

3 step:

Check for n=k+1 whether the statement

\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)

is true.

Start with the left side:

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)

According to the 2nd step,

\sum \limits_{j=1}^k2^j=2(2^k-1)

Substitute it into the \ast

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)

So, you have proved the initial statement

4 0
3 years ago
4x-5=x-1+3x I need help
labwork [276]

Answer:

x = no solutions

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

4x - 5 = x - 1 + 3x

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Combine like terms:                    4x - 5 = 4x - 1
  2. Subtract 4x on both sides:          -5 ≠ -1

Here we see that -5 does not equal -1.

∴ This equation has no solutions.

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2 years ago
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ICE Princess25 [194]
III is correct for 17
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3 years ago
Which points define the solution set
Lemur [1.5K]

There is a line and a parabola in the graph.

So, we will get the solution set from the point of intersection of both line and parabola.

Notice that the parabola and the line intersecting at two points E(1, 5) and C(-0.5,2).

So, the solution set is E(1, 5) and C(-0.5,2).

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Evil lives to go swimming at 4:05 and returns at 4:57 how long has she been gone?
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She has been gone 52 min.


57 - 5 = 52

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