You know that the discrete metric only takes values of 1 and 0. Now suppose it comes from some norm ||.||. Then for any α in the underlying field of your vector space and x,y∈X, you must have that
∥α(x−y)∥=|α|∥x−y∥.
But now ||x−y|| is a fixed number and I can make α arbitrarily large and consequently the discrete metric does not come from any norm on X.
Step-by-step explanation:
hope this helps
1) 3j + 5p = 7.60 and 1j + 2p = 2.90
2) Solving for j and p
j = 2.90 - 2p
3(2.90 - 2p) + 5p = 7.60
8.7 - 6p + 5p = 7.60
8.7 - p = 7.60
-p = -1.1
p = 1.1
1j + 2(1.1) = 2.9
j + 2.2 = 2.9
j = .7
3) The values of p and q:
p = $1.1 per pancake, j = .70 cents per glass
9.66 - you just multiple 6 by 1.61
Complete question :
Complete the expressions Write each answer as a number, a variable, or the product of a number and a variable 7(9r + 2) = 7 . 9r + 7 . ___ = ___ +
Answer:
2 ; 63r ; 14
Step-by-step explanation:
Given :
7(9r + 2)
Opening the bracket :
7*9r + 7*2 - - - - (1)
Taking the product
63r + 14 - - - - (2)
Now filling the blanks :
First blank corresponds to 2 (from (1))
Second blank corresponds to 63r (from (2))
Third blank should be 14
Combination = doesn't matter what order
Permutation = order matters
There are <u>two</u> methods to work out combinations.
Method 1 List out possibilities
123 124 125 126 127 134 135 136 137 145 146 147 156 157 167
234 235 236 237 245 246 247 256 257 267
345 346 347 356 357 367
456 457 467
567
For a total of
35 combinations.
Method 2 Use a formula.
It's a rather complicated one, so only use it if you have a lot of possibilities.

(n is the number of choices, r is the amount you choose, and ! is a function that multiplies together all numbers down to 1)