The distance between points A (3, -5) and A' (2, -3) is 2.4 units.
Given that,
The points A (3, -5) and A' (2, -3).
We have to determine,
The distance between point A and A'.
According to the question,
The distance between two points is determined by using the distance formula.
![\rm Distance \ formula = \sqrt{(x_2-x_2) ^2+ (y_2-y_2)^2](https://tex.z-dn.net/?f=%5Crm%20Distance%20%5C%20formula%20%3D%20%5Csqrt%7B%28x_2-x_2%29%20%5E2%2B%20%28y_2-y_2%29%5E2)
Then,
The distance between points A (3, -5) and A' (2, -3) is,
![\rm Distance = \sqrt{(2-3) ^2+ ((-3)-(-5))^2}\\\\ Distance = \sqrt{(-1) ^2+ (2)^2}\\\\ Distance = \sqrt{1+4}\\\\Distance = \sqrt{5}\\\\Distance = 2.4 \ units](https://tex.z-dn.net/?f=%5Crm%20Distance%20%20%3D%20%5Csqrt%7B%282-3%29%20%5E2%2B%20%28%28-3%29-%28-5%29%29%5E2%7D%5C%5C%5C%5C%20Distance%20%20%3D%20%5Csqrt%7B%28-1%29%20%5E2%2B%20%282%29%5E2%7D%5C%5C%5C%5C%20Distance%20%20%3D%20%5Csqrt%7B1%2B4%7D%5C%5C%5C%5CDistance%20%3D%20%5Csqrt%7B5%7D%5C%5C%5C%5CDistance%20%3D%202.4%20%5C%20units)
Hence, The distance between points A (3, -5) and A' (2, -3) is 2.4 units.
For more details refer to the link given below.
brainly.com/question/8069952