What growth factor would be needed to provide 1/12th of 12% interest each month

The American flag is customarily made with its width and length in the ratio of 10 to 19. Which of the following dimensions is i

saul85 [17]

You have not provided the options, therefore, I cannot give an exact answer. However, I can help you with the procedures.

We are given that the ratio between the width and the length of the flag is 10 to 19.
This means that:
$\frac{width}{length} = \frac{10}{19}$

Therefore, to get the correct choice, all you have to do is divide the width by the length, if the result is 10/19, then the dimensions given are correct.

Examples:
For length = 190 and width = 100,
width / length = 100 / 190 = 10 / 19 .........> correct choice

For length = 1.9 and width = 1,
width / length = 1 / 1.9 = 10 / 19 .......> correct choice

Hope this helps :)

3 0

2 years ago

Find the area of the shaded region. Use 3.14 as an approximation.

MA_775_DIABLO [31]

Answer:

shaded area = 113.64 cm²

Step-by-step explanation:

To find the shaded area, subtract the area of the circle from the area of the triangle.

Area of a triangle = 1/2 x base x height

⇒ area of triangle = 1/2 x 25 x 21.4 = 267.5 cm²

Area of a circle = $\pi r^2$ (where r is the radius)

From inspection, we can see that the diameter of the circle = 14 cm

Therefore, as the diameter = 2r, then r = 14 ÷ 2 = 7 cm

⇒ area of circle = 3.14 x 7² = 153.86 cm²

Shaded area = area of triangle - area of circle

⇒ shaded area = 267.5 - 153.86 = 113.64 cm²

8 0

1 year ago

Assume that a procedure yields a binomial distribution with a trial repeated n times. Use the binomial probability formula to fi

Keith_Richards [23]

Answer:

P(X = 12) = 0.0064.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 30, p = 0.2$

We want P(X = 12). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 12) = C_{30,12}.(0.2)^{12}.(0.8)^{18} = 0.0064$

P(X = 12) = 0.0064.

6 0

2 years ago

Which of the following equations have exactly one<br> solution?

Licemer1 [7]

I need to see a picture of the question so I can answer the question:)

5 0

3 years ago

30 points! Find the four arithmetic means between -17 and 32.

bearhunter [10]

Answer: - 7.2 , 2.6 , 12.4 and 22.2

Step-by-step explanation:

Let the arithmetic means be p , q , r ,s , therefore , the sequence becomes:

-17 , p , q , r , s , 32

The first term (a ) = -17

Last term (L) = 32

common difference (d) = ?

number of terms (n ) = 6

We will use the formula for calculating the last term to find the common difference. That is

L = a + (n - 1 ) d

Substituting the values , we have

32 = -17 + (6-1) d

32 = -17 + 5d

32 + 17 = 5d

49 = 5d

Therefore: d = 9.8

We can therefore find the values of p , q , r , and s

p is the second term , that is

p = a + d

p = -17 + 9.8

p = -7.2

q = a + 2d

q = - 17 + 19.6

q = 2.6

r = a + 3d

r = - 17 + 29.4

r = 12.4

s = a + 4d

s = - 17 + 39.2

s = 22.2

Therefore : the arithmetic means are : - 7.2 , 2.6 , 12.4 and 22.2

8 0

2 years ago