Answer:
23 Dimes and 8 Quarter.
Step-by-step explanation:
Important info:
31 Coins worth a total of $4.30
Note:
Dimes = .10
Quarters = .25
10 Dimes = 1.00
4 Quarter = 1.00
Question to Answer:
How many of each type of coin does she have?
Solution:
Lets get rid of the .30 cent in $4.30 so
.30 = 3 Dimes
Now $4.00,
4.00-1.00 of quarter
=
3.00 and 4 quarter..
Right now we have 3 Dimes and 4 Quarter = $1.30.
And that 7 Coins worth of $1.30.
3.00-2.00= 1.00 and 20 Dimes so now we have
23 Dimes and 4 Quarter.
And that add up to 27.
1.00-1.00 of Quarter = 4 Quarter.
so 31 worth a total of $4.30.
So that's 23 Dimes and 8 Quarter.
Check Work:
23 Dimes = $2.30 and 8 Quarter = $2.00
$2.30 + $2.00 = 4.30
Hence, The Correct Answer is 23 Dimes and 8 Quarter.
~[ RevyBreeze }~
what's the help you need?
Answer:
Step-by-step explanation:
We know that:
Only employees are hired during the first 3 days of the week with equal probability.
2 employees are selected at random.
So:
A. The probability that an employee has been hired on a Monday is:
.
If we call P(A) the probability that 2 employees have been hired on a Monday, then:
B. We now look for the probability that two selected employees have been hired on the same day of the week.
The probability that both are hired on a Monday, for example, we know is . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.
So
.
C. If the probability that two people have been hired on a specific day of the week is 
, then the probability that 7 people have been hired on the same day is:
D. The probability is 
. This number is quite close to zero. Therefore it is an unlikely bastate event.
Answer:
Step-by-step explanation:
