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20 + 5 + 2 + 3 + 1 minus 1 =30
Respuesta:
3395 L
Explicación paso a paso:
Dado que el tubo contiene 35 L de agua por metro.
Esto significa que el volumen por metro del tubo es de 35 litros.
Longitud total del tubo = 97 metros
Volumen de agua en toda la longitud del tubo:
Volumen por metro * 97
35 L * 97
= 3395 litros
Por lo tanto, peso cuando está lleno = 3395 L
Answer:
The width of the field is 4x + 20 / x² -2x -3 yards
Step-by-step explanation:
The area of a rectangular field is given by the following formula:
area = length*width
In this case we want to find the width of this field, therefore if we isolate the width in the expression above we will have a suitable expression:
width*length = area
width = area / length
So applying the data from the problem, we have:
width = [(2x + 6)/(x + 1)] / [(x² - 9)/(2x + 10)]
width = [(2x + 6)/(x + 1)]*[(2x + 10)/(x² - 9)]
width = 2(x + 3)*(2x + 10) / (x+1)*(x - 3)*(x + 3)
width = 2*(2x + 10) / (x + 1)*(x - 3)
width = 4x + 20 / x² -2x -3
Answer:
ASA
ΔFGH ≅ ΔIHG ⇒ answer B
Step-by-step explanation:
* Lets revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and
including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ
≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles
and one side in the 2ndΔ
- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse
leg of the 2nd right angle Δ
* Lets prove the two triangles FGH and IHG are congruent by on of
the cases above
∵ FG // HI and GH is transversal
∴ m∠FGH = m∠IHG ⇒ alternate angles
- In the two triangles FGH and IHG
∵ m∠FHG = m∠IGH ⇒ given
∵ m∠FGH = m∠IHG ⇒ proved
∵ GH = HG ⇒ common side
∴ ΔFGH ≅ ΔIHG ⇒ ASA
* ASA
ΔFGH ≅ ΔIHG