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3 years ago

Perform the indicated operation.(w3 +64) ÷ (4 + W)

Mathematics

1 answer:

IgorLugansk [536]3 years ago

5 0

Answer:

Answer is given below with explanations

Step-by-step explanation:

$\frac{ {w}^{3} + 64}{4 + w} = \frac{ {w}^{3} + {4}^{3} }{4 + w} \\ \: we \: know \: that \: {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} ) \\ = \frac{(w + 4)( { {w}^{2} - 4w + 16)}^{2} }{w + 4} \\ on \: cancelling \: we \: get \\ the \: answer \: \\ w^{2} - 4w + 16$

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Step-by-step explanation:

Given the equation system:

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Step 2: Sum the first row and the second row.

$\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&\frac{4}{3} &\frac{16}{3}&16\end{array}\right]$

Step 3: Multiply the second row by 3/4.

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${\qquad\qquad\huge\underline{{\sf Answer}}}$

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[ according to given figure ]

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Perform the indicated operation.(w3 +64) ÷ (4 + W)​

Perform the indicated operation.(w3 +64) ÷ (4 + W)