<span>The decay of 277 mg of an isotope is described by the function
A(t)= 277e-0.019t,
where t is time in years.
To find the amount left after 64 years,
We substitute t = 64 in the expression.
</span>A(t=64)= 277e-0.019(64)
or A(t=64) = 277 * e-1.216
= 277 * 0.29
= 82 mg
y=5x-8
5x=y+8
x=y/5+8/5 is the inverse of f(x)
Answer:

Step-by-step explanation:
We are given that


y(0)=0
y'(0)=1
By comparing with

We get


q(x)=0
p(x),q(x) and g(x) are continuous for all real values of x except 3.
Interval on which p(x),q(x) and g(x) are continuous
and (3,
By unique existence theorem
Largest interval which contains 0=
Hence, the larges interval on which includes x=0 for which given initial value problem has unique solution=
F(x) = m1x + b1
g(x) = m2x + b2
f(g(x)) = f(m2x + b2) = m1(m2x + b2) + b1 = m1m2x + b2 + b1
a.) f of g is also a linear function.
b.) slope is m1m2
Why did both of their names have to start with the same letter
x=jay hours
y=jamie huours
x=10+3y
x=43
so
43=10+3y
minus 10
33=3y
divide 3
11=y
jamies spent 11 hours