Im pretty sure it would be 4
Answer:
The interval [32.6 cm, 45.8 cm]
Step-by-step explanation:
According with the <em>68–95–99.7 rule for the Normal distribution:</em> If
is the mean of the distribution and s the standard deviation, around 68% of the data must fall in the interval
![\large [\bar x - s, \bar x +s]](https://tex.z-dn.net/?f=%5Clarge%20%5B%5Cbar%20x%20-%20s%2C%20%5Cbar%20x%20%2Bs%5D)
around 95% of the data must fall in the interval
around 99.7% of the data must fall in the interval
![\large [\bar x -3s, \bar x +3s]](https://tex.z-dn.net/?f=%5Clarge%20%5B%5Cbar%20x%20-3s%2C%20%5Cbar%20x%20%2B3s%5D)
So, the range of lengths that covers almost all the data (99.7%) is the interval
[39.2 - 3*2.2, 39.2 + 3*2.2] = [32.6, 45.8]
<em>This means that if we measure the upper arm length of a male over 20 years old in the United States, the probability that the length is between 32.6 cm and 45.8 cm is 99.7%</em>
Answer:
Hence By End of the year with monthly compounded interest it will have 5522.56 $
Step-by-step explanation:
Given:
Initial investment =5.280 $
Rate of interest =4.2%
To Find:
Amount after the 1 year
Solution:
As the investment follows the rule for compound interest as ,
A=P(1+R)^t
Here A=amount after t years
R= rate of interest , P= principal amount t is time period
So given is monthly compounded interest
so t will divided into 12 parts as there 12 months in one year.
P=5280 $ , R=4.2/12 % , t=12

^12

A=5522.56 $
Answer:
what
Step-by-step explanation:
u cant do what???,
Answer:
7m + 29
Step-by-step explanation:
You add 2m and 5m to get 7m
Then add -16 and 45 to get 29