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3 years ago

Linear equation using substitution x=16-4y 3x+4y=8

Mathematics

1 answer:

jarptica [38.1K]3 years ago

4 0

If x=16-4y then in your other equation 3x+4y=8 you can put that where x is to get:

3(16-4y)+4y=8

Then multiply brackets to get:

48-12y+4y=8

Simplify:

48-8y=8

Rearrange:

40=8y

Divide through by 8:

y=5

Then put y=5 back into x=16-4y to get x:

x=16-4(5)
x=16-20
x=-4

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The value of a is the value of B is the value of C is

enyata [817]

Answer:

A: 5

B: 9

C: 32

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3 years ago

Someone just answer this math question thingie lol. you’ll get 33 points G

Stels [109]

1) $(-2x+4)+(x-6)$ is simplified into $=-x-2$

2) $(uv-3)+(4uv+1)$ is simplified into $5uv-2\\$

3) $(11x-8)-(2x+3)$ is simplified into $-9x-11$

4) $(x^2-4)-(x-2)$ is simplified into $x^2-x-2$

5) $(12-3t-7t^2)+(1+3t-t^2)$ is simplified into $-8t^2+13$

Step-by-step explanation:

We need to solve the polynomials.

1) $(-2x+4)+(x-6)$

Solving:

$(-2x+4)+(x-6)\\=-2x+4+x-6\\Combining\,\,like\,\,terms:\\=-2x+x+4-6\\=-x-2$

So, $(-2x+4)+(x-6)$ is simplified into $=-x-2$

2) $(uv-3)+(4uv+1)$

Solving:

$(uv-3)+(4uv+1)$

Expanding:

$=uv-3+4uv+1\\Combining\,\,like\,\,terms:\\=uv+4uv-3+1\\=5uv-2\\$

So, $(uv-3)+(4uv+1)$ is simplified into $5uv-2\\$

3) $(11x-8)-(2x+3)$

Solving:

$(11x-8)-(2x+3)$

Expanding:

$=11x-8-2x-3\\Combining\,\,like\,\,terms:\,\,\\=11x-2x-8-3\\=-9x-11$

So, $(11x-8)-(2x+3)$ is simplified into $-9x-11$

4) $(x^2-4)-(x-2)$

Solving:

$(x^2-4)-(x-2)$

Expanding:

$=x^2-4-x+2\\Combining\,\,like\,\,terms:\\=x^2-x-4+2\\=x^2-x-2$

SO, $(x^2-4)-(x-2)$ is simplified into $x^2-x-2$

5) $(12-3t-7t^2)+(1+3t-t^2)$

Solving:

$(12-3t-7t^2)+(1+3t-t^2)$

Expanding:

$=12-3t-7t^2+1+3t-t^2\\Combining\,\,like\,\,terms:\\=12+1-3t+3t-7t^2-t^2\\=13+0t-8t^2\\=-8t^2+13$

So, $(12-3t-7t^2)+(1+3t-t^2)$ is simplified into $-8t^2+13$

Keywords: Solving Polynomials

Learn more about solving Polynomials at:

#learnwithBrainly

5 0

3 years ago

Read 2 more answers

Help me with the question of o.math

Lelu [443]

Answer:

Hello,

Answer 163

Step-by-step explanation:

1,7,16,28,43,..., 10th term=?

$u_1=1,u_2=7,u_2-u_1=7-1=6=2*3\\u_3=16, u_3-u_2=16-7=9=3*3\\u_4=28, u_4-u_3=28-16=12=4*3\\u_5=43, u_5-u_4=43-28=15=5*3\\\\\boxed{ u_1=1, \ u_{n+1}-u_{n}=(n+1)*3}\\\\u_{10}=163\\$