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bogdanovich [222]
3 years ago
8

16. Expand (2x - 1)(x - 3).A. 2x2 - 7X+3 B. 2x2 +7x+3C. 2x2-7X-3 D. 2x2+7X-3 E. x2+7X-3​

Mathematics
2 answers:
PolarNik [594]3 years ago
7 0

Answer:

see below

Step-by-step explanation:

the simple answer is a if you need an explanation just comment

Inessa [10]3 years ago
6 0

Answer:

Hey there!

(2x-1)(x-3)

2x^2-1x-6x+3

2x^2-7x+3

Hope this helps :)

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I think this is the equationT(m)= 17.50m
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2 years ago
Uhhhhhh????????????!
mariarad [96]

Answer:

2y + 3 = 4y + 2; y = 1/2

Step-by-step explanation:

to find this equation we can use the ys and the 1s to create an equation

so

in the left side

there are 2 ys and 3 1s

your equation is

2y + 3

on the other side

it is

4 ys and 2 1s

so

4y + 2 is your equation

then yo uset them equal to each other

2y + 3 = 4y + 2

if you must solve

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2 years ago
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Step-by-step explanation:

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3 years ago
Austin qualified for a $30,000 loan with 7.49% interest in order to buy a new ski boat. The term of his loan is 10 years and his
sertanlavr [38]

Answer:

$12,714

Step-by-step explanation:

Loan Amount=$30,000

Monthly Payment =$355.95.

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Total Payment to be made by Austin =120 X 355.95=$42,714

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7 0
3 years ago
An urn contains 12 balls, of which 4 are white.
wel

Answer:

a) \frac{1}{3}

b) \frac{4}{12}\,,\,\frac{4}{11}\,,\,\frac{4}{10}\,,...

Step-by-step explanation:

Number of balls in the urn = 12

Number of white balls in the urn = 4

So, number of balls which are not white = 12 - 4 = 8

We know that probability = No. of outcomes/Total number of outcomes

Let A_i\,,\,B_i\,,\,C_i denotes the event of getting white ball by A, B and C

a) each ball is replaced after being drawn.

Probability = Number of white balls/Total number of balls

Solution: P(A_i)=P(B_i)=P(C_i)=\frac{4}{12}=\frac{1}{3}

b)the balls that are withdrawn are not replaced.

Solution:

If A wins: P(A_1)=\frac{4}{12}=\frac{1}{3}

If A lost and B wins: P\left ( B_1|A_1^{c} \right )=\frac{4}{11}

If A and B lost and C wins: P\left ( C_1|A_1^{c}\,B_1^{c} \right )=\frac{4}{10}

and so on....

4 0
4 years ago
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