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katen-ka-za [31]
3 years ago
5

The____is measure of the number of waves that pass a point in a given amount of time

Physics
2 answers:
bagirrra123 [75]3 years ago
5 0

Answer:

frequency

Explanation:

The <u>frequency</u> is a measure of the number of waves that pass a point in a given amount of time.

jekas [21]3 years ago
3 0
The Frequency is the number of waves that pass a given point in a certain amount of time .
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What moves electrons in a circuit?
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I think it’s will be B
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Which of the following is NOT an example of kinetic energy being converted to potential energy
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The answer is c cause it is not moving like the other 3 
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Please show work and tell me how you did it.
Ilya [14]

Explanation:

1) speed of bicycle = \frac{distance}{time}

speed of bicycle= \frac{20}{2}

speed of bicycle = 10 miles/hour

2)speed of rocket = \frac{distance}{time}

speed of rocket= \frac{9000}{12.12}

speed of rocket= 742.57 meter/second

3)speed of jet plane = \frac{distance}{time}

speed of jet plane= \frac{528}{4}

speed of jet plane= 132 meter/second

4)speed = \frac{distance}{time}

time = \frac{distance}{speed}

time of trip= \frac{350}{80}

time of trip = 4.375 hour

5) Distance = speed × time

Distance = 6 × 3 × 60

Distance = 1080 meter

6) Average speed = \frac{total distance}{total time}

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Average speed = 81.6 km/hour

7) Time = \frac{Distance}{speed}

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4 0
3 years ago
A 23.0 kg child plays on a swing having support ropes that are 2.10 m long. A friend pulls her back until the ropes are 45.0 deg
Romashka [77]

Answer:

a. 139.748J

b.3.486m/s

c.zero

Explanation:

a. Given the mass of the child as 23.0kg, rope length is 2.1mand incline is 45°

Potential energy during release is calculated as:PE=mgh

#Find vertical difference of when the swing is at rest (2.1m) and when the child is pulled back.

Find the height when the child is pulled back:

cos 45\textdegree=y/2.10\\\\y=1.48m

#therefore,vertical difference is 2.1m-1.48m=0.62m

\therefore PE=mgh\\\ \ =23.0kg\times 9.8m/s^2\times 0.62m\\\ \ =139.748J

#Hence the potential energy during release is 139.748J

b. From a, above, we have PE=139.748J, M=23.0kg.

At the bottom, all the PE will be transferred into KE. Potential energy is calculated as:

KE=0.5mv^2\\\\mv^2=2KE\\\\v=\sqrt{2KE/m}\\\\v=\sqrt{2\times 139.748J/23.0}\\\\v=3.486m/s

#Hence the velocity at the bottom of the swing is 3.486m/s

c. Work is calculated as the product of force by distance.

From a, b above we have mass as 23.0kg .

-since the distance of the ropes remained constant the change in distance is zero:

W=mgd\\=23.0\times 9.8m/s^2\times 0\\=0

Therefore the work in the ropes is 0,zero.

8 0
3 years ago
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