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iren2701 [21]
3 years ago
13

A car engine has power than a horse because a car engine does the same amount of work in time. Yasmin and Raj each had 10 boxes

of equal weight to stack next to each other on the same shelf, at the same height and in the same arrangement. Yasmin completed the task in 2 minutes, while Raj took 3 minutes to stack his boxes. Raj applied power than Yasmin because his stacking took time to do the same amount of work.
Physics
2 answers:
vfiekz [6]3 years ago
6 0

Answer:

more less less more

Explanation:

labwork [276]3 years ago
4 0

Answer:

A car engine has more power than a horse because a car engine does the same amount of work in time. Yasmin and Raj each had 10 boxes of equal weight to stack next to each other on the same shelf, at the same height and in the same arrangement. Yasmin completed the task in 2 minutes, while Raj took 3 minutes to stack his boxes. Raj applied less power than Yasmin because his stacking took more time to do the same amount of work.

Explanation:

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The best explanation is the <em>difference</em> between the inside <em>temperature</em> and the outside temperature.

If the player doesn't change his emboucher (muscles and position of his lips), then the pitch produced by the instrument depends only on the physical dimensions of its plumbing, and the speed of sound in the tube.

BOTH of those things change slightly when the temperature changes.

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calculate the energy spent on spraying a drop of mercury of 1 cm radius into 10^6 droplets all of same radius. surface tension o
WARRIOR [948]

Answer:

ANS : .Energy spent on spraying =4.3542*10^{-4}J

Explanation:

<em>Given:</em>

  • <em>Radius of mercury = 1cm initially ;</em>
  • <em>split into 10^{6} drops ;</em>

Thus, volume is conserved.

i.e ,

\frac{4}{3} \pi R_{o}^{3} = 10^{6}*\frac{4}{3} \pi R_{n}^{3}\\R_{n}=\frac{R_{o}}{10^{2}} = \frac{1cm}{100} = 0.01 cm

  • Energy of a droplet = TΔA

Where ,

  • <em>T is the surface tension </em>
  • <em>ΔA is the change in area</em>

Initial energy E_{i} = T*A_{i}\\= 0.0035 * 4 *\pi *0.01^{2}\\=4.398*10^{-6}J

Final energy E_{f}=10^{6}*T*A_{f}\\=10^{6}*0.0035*4*\pi *(0.0001)^2\\=4.39823*10^{-4}

∴  .Energy spent on spraying = =E_{f}-E{i}\\=(439.823-4.39823)*10^{-6}\\=4.3542*10^{-4}J

ANS : .Energy spent on spraying =4.3542*10^{-4}J

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Weight is a force caused by gravity. The weight of an object is the gravitational force between the object and Earth.
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What class is this for?
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What force acts on all objects, all the time on Earth?
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The force that acts on all objects, all the time on Earth is gravitational force.

The force that surface exert on an object perpendicularly is normal reaction.

<h3>What force acts on all objects, all the time on Earth?</h3>
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The force due to gravity on object's is calculated by applying Newton's second law of motion as follows;

F = mg

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The force that surface exert on an object perpendicularly is normal reaction.

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