Using the midpoint formula we get:
(x,y)=(0+5/2, 0+12/2) or (5/2, 6) as the midpoint.
Answer:
B=-9
Step-by-step explanation:
Technically, I didn't solve it. I used an algebra calculator online called m a t h w a y. It helps a lot but if you really need to know how to solve it on pencil and paper I cannot help you.
I had to space out the website so it let me submit this answer btw
Answer:
m = 1 and b = 5/7
Step-by-step explanation:
Take two of the points. The first two. (7, 5) and (8, 6).
We can find the slope using:
y2-y1/x2-x1
We can sub in the values:
6-5/8-7 = 1/1 = 1
So the slope is 1
now, putting this into y=mx+b, and using one of the coordinates from earlier, we can solve for b:
5 = (1)(7) + b
b = 5/7
Therefore, m = 1 and b = 5/7
Hope this helps!
The projectile has constant horizontal speed all the time and we can use this formula
x=Vax*t, where t is time it (projectile) takes to reach x=1000m
t=x/Vax=1000/50=20s
As we know we can split projectile trajectory in two parts and the time for each part is equal. We can conclude that time t=20s belong to first part where projectile is going up.
Formula for this type of movement is y=Vay-(gt∧2)/2
If we take acceleration of gravity g=10m/s∧2
we get y=200*20-(10*20∧2)/2=4000-2000=2000m
But if I calculate time it takes the highest point I get
t=Vay/g=200/10=20s
The highest point for that time is
y= H=Vay∧2/2g=200∧2/2*10=40000/20=2000m
This happened because the projecile is fired from the edge of a cliff which is above the sea line.
Good luck!!!
Answer:
The area of the square is 85 units^2
Step-by-step explanation:
Okay, here in this question, we are interested in calculating the area of the unknown square.
Kindly note that, since each of the other shapes are squares too, it means that the length of their sides is simply the square root of their areas.
Thus, the length of the squares are ;
√35 units and √50 units respectively
Now to find the area of the larger square, we employ the use of Pythagoras’ theorem which states that the square of the hypotenuse is equal to the sum of the squares of the two other sides
Let’s call the unknown length X
x^2 = (√35)^2 + (√50)^2
x^2 = 35 + 50
x^2 = 85
x = √85 units
Now as we know that the area of a square is simply the length of the side squared,
The area of the biggest square is simply (√85)^2 = 85 units^2
