All categories

2 years ago

HELP ME I WILL GIVE BRAINLIEST TO THE FIRST PERSON TO DO IT.

Mathematics

1 answer:

MA_775_DIABLO [31]2 years ago

5 0

Step-by-step explanation:

Here you go,

number 7 = 26

number 9 = 66

number 8 = 79

number 6 = 31

You might be interested in

3x + 17 + 5x = 7x + 10

Sphinxa [80]

Answer: x=-3

Step-by-step explanation:

First you add 3x+5x cause they are both variables.They equal 8x.

Then you subtract 7x from both sides to get x+17=10

then you subtract 17 from both sides.

you will get x= -3

Hope that helps!

5 0

2 years ago

Read 2 more answers

Find measure of angle b

nordsb [41]

I cant see the problem

3 0

3 years ago

If there 3 feet in a yard and a football field is 100 yards long how long is the football field in feet

givi [52]

300 because you have to multiply 100 and 3

6 0

2 years ago

Read 2 more answers

What are the values of mode and median in the following set of numbers? 1,3,3,6,6,5,4,3,1,1,2 Mode: 1, 2, Median: 2 Mode: 1,3, M

AURORKA [14]

<h3>given:</h3>

$1 \: 3 \: 3 \: 6 \: 6 \: 5 \: 4 \: 3 \: 1 \: 1 \: 2$

the mode and median of the given numbers set.

<h3>solution:</h3><h3>mode:</h3>

the most frequently occurred number.

$mode = 1 \: and \: 3$

<h3>median:</h3>

first arrange all the numbers in either decending or ascending order, then find the number in the middle.

$1 \: 1 \: 1 \: 2 \: 3 \: 3 \: 3 \: 4 \: 5 \: 6 \: 6$

$median = 3$

hence, the median of the following data set is 3 and the mode is 1 and 3

8 0

1 year ago

There is 1500 ft of fencing available to make 6 identical pens. Find the maximum area for EACH pen (meaning maximum of one pen).

hjlf

Answer:

The maximum area is therefore is 93750 ft²

Step-by-step explanation:

The given parameter are;

The a]length of fencing available = 1500 ft.

The perimeter of the figure = 9·x + 4·y

Therefore, 9·x + 4·y = 1500 ft.

The area of the figure = 6 × (x × y) = 3·x × 2·y

From the equation for the perimeter, we have;

9·x + 4·y = 1500

y = 1500/4 - 9/4·x = 375 - 9/4·x

y = 375 - 9/4·x

Substituting the value of y in the equation for the area gives;

Area = 3·x × 2·y = 3·x × 2·(375 - 9/4·x) = 2250·x - 27/2·x²

Area = 2250·x - 27/2·x²

The maximum area is found by taking the derivative and equating to zero as follows;

d(2250·x - 27/2·x²)/dx = 0

2250 - 27·x = 0

x = 2250/27 = 250/3

x = 250/3

y = 375 - 9/4·x = 375 - 9/4×250/3 = 187.5

The maximum area is therefore, 3·x × 2·y = 3 × 250/3 × 2 × 187.5 = 93750 ft²

The maximum area is therefore = 93750 ft.²

4 0

2 years ago