Answer:
-11
Step-by-step explanation:
The generic solution to ...
- a + b = sum
- a - b = difference
Can be found by adding the two equations:
(a+b) + (a-b) = (sum) + (difference)
2a = (sum + difference)
a = (sum + difference)/2
___
Our particular solution is ...
a = (-44 +22)/2 = -11
The greater of the two numbers is -11.
___
The other number is -33.
Answer:
= -33
Step-by-step explanation:
Answer:
6 and 3
Step-by-step explanation:
5.8 to the nearest whole is 6
3.147 to the nearest whole is 3
30 bags of flour + 4 bags of sugar = 42.6 kg
each bag of sugar weighs 0.75 kg
each bag of flour weighs x kg = ?
If you would like to know what is the weight of each bag of flour, you can calculate this using the following steps:
30 * x + 4 * 0.75 kg = 42.6 kg
30 * x + 3 kg = 42.6 kg
30 * x = 42.6 kg - 3 kg
30 * x = 39.6 kg /30
x = 39.6 kg / 30
x = 1.32 kg
Result: Each bag of flour weighs 1.32 kg.
The nth term of an AP = a + (n - 1)d
The pth term of the AP = a +(p - 1)d = 1/q
The qth term of the AP = a +(q - 1)d = 1/p
Sum of nth term = (n/2)(2a + (n - 1)d)
Sum for 20th term = (20/2)(2a + (20- 1)d) = 10(2a + 19d)
a +(p - 1)d = 1/q .....(a)
a +(q - 1)d = 1/p ......(b)
Equation (a) - (b)
a - a + (p - 1)d - (q - 1)d = 1/q - 1/p
pd - d -qd + d = (p - q)/pq
pd - qd = (p - q)/pq
(p - q)d = (p - q)/pq
Cancel out (p - q) from both sides
d = 1/(pq)
Recall a +(p - 1)d = 1/q .....(a)
a +(p - 1)(1/pq)= 1/q
a + (p - 1)/(pq) = 1/q
a = (1/q) - (p - 1)/(pq)
a = (p - (p - 1))/(pq)
a = (p - p + 1) / (pq)
a = 1/(pq)
a = 1/(pq), d = 1/(pq)
Recall sum of 20 terms:
10(2a + 19d)
10(2*(1/(pq)) + 19*(1/(pq)))
10 ( 2/(pq) + 19/(pq)) = 10* (2 + 19)/(pq)
= 10*21/(pq)
= 210 / (pq)
Sum of the 20 terms = 210/(pq)
Hope this explains it.
