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miv72 [106K]
3 years ago
15

Convert (-2/sqrt[3] , 2) to polar coordinates

Mathematics
1 answer:
anyanavicka [17]3 years ago
5 0
If you have these conditions:

1. (r ,theta) where r > 0 
<span>2. (r, theta) where r < 0
</span>
The solution would be:

<span>r = sqrt(x^2 + y^2) 

t = arctan(y/x) 


r = sqrt(12 + 4) = sqrt(16) = +/- 4 

t = arctan(2 / -2sqrt(3)) = arctan(-1 / sqrt(3)) = 5pi/6 , 11pi/6 


1) 
r > 0 
(4 , 11pi/6) 

2) 
r < 0 
(-4 , 5pi/6)
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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I REALLY NEED HELP WORTH 10 POINTS URGENT!!!!!
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Answer:

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Step-by-step explanation:

<u>Composite Function</u>

Given f(x) and g(x) real functions, the composite function named fog(x) is defined as:

(f\circ g)(x)=f(g(x))

For practical purposes, it can be found by substituting g into f.

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Computing the composite function:

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Operating:

(f\circ g)(x)=3x^2-18+1

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Now evaluate for x=4

(f\circ g)(4)=3(4)^2-17=48-17

\boxed{(f\circ g)(4)=31}

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