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Sati [7]
4 years ago
13

What’s the derivative of (2x+9)^3

Mathematics
1 answer:
larisa86 [58]4 years ago
8 0

If f(x) = (2x+9)^3, f '(x) = 3(2x+9)^2*(2), or f '(x) = 6(2x+9)^2.  Here we used the power rule with chain rule to find the derivative.

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What is the estimated standard error for a sample of n = 9 scores with ss = 288?
gladu [14]

The estimated standard error for a sample of n = 9 scores with ss = 288 is 2. Among your choices, it should be B; s2 = 36 and sM  = 2.

Hope that helps!

8 0
1 year ago
In circle O, AC and BD are diameters. Circle O is shown. Line segments B D and A C are diameters. A radius is drawn to cut angle
aivan3 [116]

Answer:

120

Step-by-step explanation:

Got it right on the assigment

6 0
4 years ago
Susan enlarged a rectangle with a height of 5 cm and length of 12 cm on her computer. The length of the new rectangle is 18 cm.
vodka [1.7K]
5/12=x/18
x=7.5
The height of new triangle is 7.5cm
7 0
3 years ago
The area of a rectangle varies jointly as its length and width. Find the equation of joint variation if A = 60ft², l = 15ft, and
MaRussiya [10]

Answer: The length is 6 feet and the width is 10 feet.

Step-by-step explanation: The question has specified the area as 60 (square feet) and the length and width are yet unknown. However we know that the length is 4 feet less than the width. What this means is that, if the width is W, then the length is W - 4.

We can now write an equation for the area of the rectangle as follows;

Area = L x W

60 = (W - 4) x W

60 = W^2 - 4W

If we rearrange all terms on one side of the equation, we now have

W^2 - 4W - 60 = 0

This is a quadratic equation and by factorizing, we now have

(W + 6) (W - 10) = 0

Hence,

Either W + 6 = 0 and then W = -6

Or W - 10 = 0 and then W = 10

We know that the side of the rectangle cannot be a negative value, so we go with W = 10.

Having calculated W as 10, the length now becomes

L = W - 4

L = 10 - 4

L = 6

Therefore, length = 6 feet and width = 10 feet

5 0
3 years ago
Read 2 more answers
BRAINLIEST IF CORRECT AND EXPLANATION <br> Solve each equation in the interval [0, 2pi)
victus00 [196]

Answer:  \frac{\pi}{2}, \ \frac{5\pi}{4}, \ \frac{3\pi}{2}, \ \frac{7\pi}{4}

We can write the four solutions as:  pi/2, 5pi/4, 3pi/2, 7pi/4

=============================================================

Work Shown:

\sqrt{2}\cot(x)\sin(x)+\cot(x)=0\\\\\cot(x)\left(\sqrt{2}\sin(x)+1\right)=0\\\\\cot(x)=0 \ \text{ or } \ \sqrt{2}\sin(x)+1=0\\\\\frac{\cos(x)}{\sin(x)}=0 \ \text{ or } \ \sqrt{2}\sin(x)=-1\\\\\cos(x)=0*\sin(x) \ \text{ or } \ \sin(x)=\frac{-1}{\sqrt{2}}\\\\\cos(x)=0 \ \text{ or } \ \sin(x)=\frac{-\sqrt{2}}{2}\\\\

Use the unit circle or reference sheet to find that \cos(x)=0 leads to x = \frac{\pi}{2} \ \text{ and } \ x =  \frac{3\pi}{2} when working with the interval [0,2pi)

Also, use of the unit circle would show that \sin(x)=\frac{-\sqrt{2}}{2} leads to x = \frac{5\pi}{4} \ \text{ and } \ x =  \frac{7\pi}{4} when working with the interval [0,2pi)

-----------

Overall, the four solutions on the interval [0, 2pi) are

\frac{\pi}{2}, \ \frac{5\pi}{4}, \ \frac{3\pi}{2}, \ \frac{7\pi}{4}

To verify these solutions, plug them in one at a time into the original equation. You should end up with 0 = 0 after simplifying. Make sure your calculator is in radian mode.

3 0
3 years ago
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