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kramer
3 years ago
9

For a horizontal launch (θ0 = 0) at a fixed height ℎi > 0, are the statements below correct? (Assuming friction can be ignore

d.)
(1) The object is moving along a straight line.
(2) The acceleration in the horizontal direction is zero.
(3) No matter how fast the object is launched, the travel time is always the same.
(4) No matter how fast the object is launched, the horizontal travel distance Δx is always the same.
Mathematics
1 answer:
Marizza181 [45]3 years ago
5 0

Answer:

1) False. 2) True. 3) True. 4) False.

Step-by-step explanation:

1) False. The force of gravity will drive it down. The path will form a parabola.

2) True. There is no variation in the velocity in the horizontal axis and no force applied so the acceleration is zero.

3) True. The travel time depends on the height and the acceleration of gravity, and independent of the velocity of the rocket at launch.

4) False. The travel distance depends on the initial velocity of the rocket (at launch).

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Lelu [443]

Step-by-step explanation:

a. that's the best answer that suits the question per day you multiply by 22

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3 years ago
Using substitution to solve the system below, what expression should be substituted into the first equation? 2x-4y=-4 and x+2y=8
inna [77]

Answer:

Given the system of equation:

2x-4y=-4                    ......[1]

x+2y=8                      ......[2]

we can rewrite equation [2] as;

x = 8-2y                ......[3]

Substitute equation [3] into [1] to eliminate x, and solve for y;

2(8-2y)-4y = -4

Using distributive property: a\cdot (b+c) = a\cdot b+ a\cdot c

16-4y -4y = -4

Combine like terms;

16 - 8y = -4

Add 4 to both sides we have;

20 - 8y = 0

Add 8y to both sides we have;

20 = 8y

Divide 8 to both sides we have;

y = 2.5

Substitute the y-value in [3] we have;

x = 8-2(2.5)

x = 8 - 5 = 3

Therefore, the  expression should be substituted into the first equation is, x = 8-2y  and also the value of x = 3 and y = 2.5

5 0
3 years ago
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For number 2 I know the answer but I just need work so if you could please explain the work I’d be thankful
const2013 [10]

Answer:

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4 0
3 years ago
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noname [10]

Answer:

Replace all occurrences of y with 2x−1 in each equation.

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y=2x−1

Remove any equations from the system that are always true.

y=2x−1

Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

Note:

1. (a + b)^2 = a^2 + 2ab + b^2

2. (a - b)^2 = a^2 - 2ab + b^2

3. sin^2θ + cos^2θ = 1

(sinθ -cosθ)^2 - (sinθ + cosθ)^2

= sin^2θ - 2sinθcosθ + cos^2θ - (sin^2θ + 2sinθcosθ + cos^2θ)

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3 years ago
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