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liberstina [14]
3 years ago
13

If, in

Physics
1 answer:
STatiana [176]3 years ago
5 0

Answer:

a)   λ = 121.5 nm , b) 102.6, 97, 91.1 nm

Explanation:

Bohr's model describes the energy of the hydrogen atom

      E_{n} = k² e² / 2m (1 / n²)

A transition occurs when the electron passes from n level to a lower one

       E_{i} -  E_{n} = k² e² / 2m (1 / n_{i}² - 1 /  n_{f}²)

Planck's relationship is

        E = h f = h c / lam

        hc /λ =  k² e²/ 2m(1 / n_{i}² - 1 /  n_{f}²)

        1 / λ = [k² e² / 2m h c] (1 / n_{i}² - 1 /  n_{f}²)

        1 /λ = Ry] (1 / n_{i}² - 1 /  n_{f}²)

a) the first element of the series occurs for n_{f} = 2

        1 / λ = 1.097 10⁷ (1- 1/2²)

        1 / λ = 1.097 10⁷ (1- 0.25)

        1 / λ = 0.82275 10⁷

        λ = 1.215 10⁻⁷ m

        λ = 1,215 10⁻⁷ m (10⁹nm / m)

        λ = 121.5 nm

b) the next elements of the series occur to

n_{f}       n_{i}    1 /λ                            λ (10-7m)       λ (nm)

3        1     1,097 10⁷ (1-1 / 9)     1,0255           102.6

4        1     1,097 10⁷ (1-1 / 16)   0.9723            97.2

∞       1      1,097 10⁷ (1 - 0)     0.91158           91.1

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AysviL [449]

Answer:

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Explanation:

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4 0
3 years ago
Penguin #1 travels at speed v=0.9 c relative to penguin #2. At the instant that both are at the origin, they synchronize their c
Alekssandra [29.7K]

Answer:

L = 0.44 [m]

Explanation:

Here we can use the Lorentz transformation related to length to solve it:

L=L_{0}\sqrt{1-\beta^{2}}

<u>Where</u>:

L₀ is the length of the moving reference frame (penguin #1)

L is the length of the fixed reference frame (penguin #2)

β is the ratio between v and c

<u>We know that v = 0.9c so we can find β.</u>

\beta = \frac{0.9c}{c}=0.9

L=1 [m]\sqrt {1-0.9^{2}} = 0.44 [m]

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I hope it helps you!

6 0
4 years ago
The wheelchair starts from rest. It accelerates at a constant rate until it has a speed of 1.5 m/s. The wheelchair travels a dis
anastassius [24]
<h2><em><u>Answ</u></em><em><u>er</u></em><em><u>:</u></em><em><u>-</u></em></h2>

\pink{\bigstar} The acceleration of the wheelchair is \large\leadsto\boxed{\tt\purple{0.5625 \: m/s^2}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

<h3>• <u>Given</u><u>:</u><u>-</u></h3>

  • Initial velocity of the wheelchair = 0 m/s

  • Final velocity of the wheelchair = 1.5 m/s

  • Distance covered by the wheelchair = 2 m

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

<h3>• <u>To</u><u> </u><u>Find</u><u>:</u><u>-</u></h3>

  • Acceleration of the wheelchair = ?

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

<h3>• <u>Solution</u><u>:</u><u>-</u></h3>

We know,

• <u>Third</u><u> </u><u>Eq</u><u>uation</u><u> of</u><u> Motion</u><u>:</u><u>-</u>

\pink{\bigstar} \large\underline{\boxed{\bf\green{v^2 - u^2 = 2as}}}

where,

  • u = Initial velocity

  • v = Final velocity

  • a = Acceleration

  • s = Distance covered

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• <u>S</u><u>u</u><u>b</u><u>s</u><u>t</u><u>i</u><u>t</u><u>u</u><u>t</u><u>i</u><u>n</u><u>g</u><u> </u><u>the</u><u> </u><u>values</u><u> </u><u>in</u><u> </u><u>th</u><u>e</u><u> </u><u>Formula</u><u>:</u><u>-</u>

➪ \sf (1.5)^2 - (0)^2 = 2 \times a \times 2

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ \sf 2.25 - 0 = 4 \times a

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ \sf 2.25 = 4 \times a

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ \sf a = \dfrac{2.25}{4}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

★ \large{\bold\red{a = 0.5625 \: m/s^2}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Therefore, the acceleration of the wheelchair is 0.5625 m/s².

7 0
3 years ago
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devlian [24]

Answer:

(B.) 50N applied to the left

Explanation: look at the arrows

5 0
3 years ago
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Anestetic [448]
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8 0
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