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Sergio039 [100]
3 years ago
14

A car traveling 25 m/s to the north collides with a car traveling 15 m/s to the south. Each car has a mass of 1100 kg. If the sy

stem is defined as the two cars, what is the change in momentum of the system due to the collision?
A. 27,500 kg*m/s
B.16,500 kg*m/s
C.44,000 kg*m/s
D. 0 kg*m/s
Physics
2 answers:
kirill [66]3 years ago
8 0

conservation of momentum ... that before = that after ... change zero

grigory [225]3 years ago
3 0

Answer:

The change in momentum of the system due to the collision is 0 kg-m/s.

Explanation:

It is given that,

Initial velocity of car 1, u_1=25j\ m/s (north)

Initial velocity of car 2, u_2=-15j\ m/s (south)

Mass of each cars, m_1=m_2=1100\ kg

It may be the case of elastic collision, such that they will exchange their velocities. So, the final speed of both the cars will be :

Final velocity of car 1, v_1=-15j\ m/s (south)

Final velocity of car 2, v_2=25j\ m/s (north)

The change in momentum of the system due to the collision is equal to the final momentum minus initial momentum. So, it is equal to 0 kg-m/s. Hence, the correct option is (d) " 0 kg-m/s".                                                                                      

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Object A has 25 J of kinetic energy. Object B has one-quarter the mass of object A.By what factor does the speed of each object
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Answer:

The speed of object B is 2 times of speed of object A.

Explanation:

Given that,

Kinetic energy of object A = 25 J

Mass of object B m_{B}=\dfrac{1}{4}m_{A}

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We need to calculate the factor of the speed of the object

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Put the value into the formula

\dfrac{1}{2}m_{A}\times v_{A}^2=\dfrac{1}{2}\times\dfrac{1}{4}m_{A}\times v_{B}^2

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v_{A}=\dfrac{1}{2}v_{B}

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Which of the following is true regarding the speed of earthquake waves?
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Sergeeva-Olga [200]

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Explanation:

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2) Since the cylinder turns one complete revolution, the distance run by the cable equals the circumference of cylinder.

3) Hence, you need to calculate the circumference of the cylinder, which is calcualted with the formula C = 2π × radius.

The radius is half the diameter: 1.2 m / 2 = 0.6 m

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4) Now, assuming that the elevator went from the initial speed of 2.7 m/s to the complete stop (Vf = 0), with uniform acceleration (deceleration), you use the corresponding formulas:

i) Vf² = Vo² - 2ad ⇒ 2ad = Vo² - Vf² ⇒ a = [Vo² - Vf²] / (2d)

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