(2m west) + (3m south) + (4m east) + (1m north) =
[ (2m west)+(4m east) ] + [ (3m south)+(1m north) ] =
[ (-2m east)+(4m east) ] + [ (3m south)-(1m south) ] =
(2m east) + (2m south)
Now, so far, we have the orthogonal (perpendicular) components of the displacement ... the North/South component and the East/West component.
To combine these, it's time for Pythagoras:
Displacement = √[ (2m)² + (2m)² ]
Displacement = √ (4m² + 4m²)
Diplacement = √8m²
<em>Displacement = 2.83 meters Southeast</em>
