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trapecia [35]
3 years ago
13

As temperature rises from 25°C to 60°C, the material _______ heat and its kinetic energy _________ as the material goes through

vaporization to become a gas.
Physics
2 answers:
Rom4ik [11]3 years ago
5 0

Answer:

As temperature rises from 25°C to 60°C, the material absorb heat and its kinetic energy increases as the material goes through vaporization to become a gas.

Explanation:

Heat is said to be the amount of energy present in a substance . it might also be potential energy.

Kinetic energy talks about an energy in motion.

Temperature rise causes an increase in the heat energy as the material tends to absorb more heat and become more energize. Temperature rise also causes an increase in the kinetic energy of the molecules of a substances. As the temperature rise the molecules of the material gain more kinetic energy and the speed at which the molecule move increases to cause faster interaction. Since the material turned to gas their is bound to be higher kinetic energy causing the material to vaporize.

jeyben [28]3 years ago
3 0

Answer:

absorbs,increases

Explanation:

b/c the material absorbs heat and its kinetic energy increases as the material goes through vaporization to become a gas

p.s can you put me as brainliest if i got it right plz????

thanks

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Explanation:

V=40m/s

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3 years ago
A major-league pitcher can throw a ball in excess of 40.1 m/s. If a ball is thrown horizontally at this speed, how much will it
mote1985 [20]

Answer:

The ball will drop 0.881 m by the time it reaches the catcher.

Explanation:

The position of the ball at time "t" is described by the position vector "r":

r = (x0 + v0x · t, y0 + v0y · t + 1/2 · g · t²)

Where:

x0 = initial horizontal position.

v0x = initial horizontal velocity.

t = time.

y0 = initial vertical position.

v0y = initial vertical velocity.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

When the ball reaches the catcher, the position vector will be "r final" (see attached figure).

The x-component of the vector "r final", "rx final", will be 17.0 m. We have to find the y-component.

Using the equation of the x-component of the position vector, we can calculate the time it takes the ball to reach the catcher (notice that the frame of reference is located at the throwing point so that x0 and y0 = 0):

x = x0 + v0x · t

17.0 m = 0 m + 40.1 m/s · t

t = 17.0 m/ 40. 1 m/s = 0.424 s

With this time, we can calculate the y-component of the vector "r final", the drop of the ball:

y = y0 + v0y · t + 1/2 · g · t²

Initially, there is no vertical velocity, then, v0y = 0.

y = 1/2 · g · t²

y = -1/2 · 9.8 m/s² · (0.424 s)²

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The ball will drop 0.881 m by the time it reaches the catcher.

8 0
3 years ago
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Alex787 [66]

Answer:

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2 years ago
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Vladimir79 [104]
I believe it would be 2m/s.
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