All categories

3 years ago

I need help on this

Mathematics

2 answers:

xeze [42]3 years ago

4 0

Answer:

Step-by-step explanation:

because 4% is the lowest and 4 1/4 is the biggest

Marina CMI [18]3 years ago

3 0

I think it's answer choice a

You might be interested in

(b) 3 hour 45 minute

lana66690 [7]

Answer:

what is your question can u explain

4 0

3 years ago

An aerospace company has submitted bids on two separate federal government defense contracts. The company president believes tha

gulaghasi [49]

Answer:

1)28.8%

2)28.8%

3)43.6%

Step-by-step explanation:

1))Probability of wining both = Probability that first contract is won* Probability that second contract is won = 0.4 * 0.72 = 0.288 = 28.8%

2)Probability of losing = 1 - Probability of winning

Probability that they will lose both contracts = Probability that first contract is lost * Probability that second contract is lost = (1 - 40/100) * (1 - 54/100) = 0.276 = 27.6%

3)Probability that any one is won = 1 - both contracts are won - both contracts are lost = 1 - 0.276 - 0.288 = 0.436 = 43.6%

7 0

3 years ago

On a coordinate plane, how are the locations of the points (-4 , 8) and (-4 , -8) related?

STALIN [3.7K]

Answer:

A. reflection across the y-axiss

Step-by-step explanation:

Given:

The locations of the two points are (-4 , 8) and (-4 , -8).

To find:

The relation between two points.

From the given points (-4, 8) and (-4 , -8), it is clear that the y-coordinates are same but the sign of x-coordinates are opposite.

If a figure is reflected across the y-axis, then we change the sign of x-coordinate and the y-coordinates remain same, i.e.,

$(x,y)$ → $(-x,y)$

For (-4,8)

$(-4,8)$ → $(-4,-8)$

So, it is reflection across the y-axis.

Therefore, the correct option is A.

6 0

3 years ago

A bag contains red, green, and yellow marbles. The probability of selecting a red marble is 35%. What is the probability of not

KonstantinChe [14]

Probablity of selecting a red marble= 35%

Probablity of not selecting a red marble= 100%-35%

=65%

Hope it helps you. Please mark brainliest.

6 0

3 years ago

Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$

Anna [14]

Answer:

$\large\boxed{1\dfrac{1}{3}\ u^2}$

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

$x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1$

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

$\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}$

6 0

3 years ago