All categories

2 years ago

Z=Xm+n-p,solve for x

Mathematics

1 answer:

timama [110]2 years ago

6 0

z=xm+n-p

We need to isolate x to one side I will do that on the left side so it looks cleaner, therefore I will first flip the equation.

xm+n-p=z

Now move the n and p to the right side

xm=z-n+p

x=(z-n+p)/m

Hope this helped, if you have any questions about this just comment and I will come answer.

You might be interested in

A manufacturing company with 450 employees begins a new product line and must increase their number of employees by 18%. How man

Sonja [21]

You just multiply 450 by .18 and it'll give you the 18% you have to add to 450.
So the equation would look like:

450(.18)=81

Which you then add:

450+81= 531

So 531 is your total!

6 0

3 years ago

Read 2 more answers

Abby feeds her dog 1 1/2 cups of food each day, and Braxton feeds his dog 4 1/2 cups of food each day. In one week, how many tim

ddd [48]

Solution:

Abby's dog: 1.5 cups of food
Braxton's dog: 4.5 cups of food

Looking at the information we got, we can say that Braxton's dog eats more. Let's put them into ratio form (Braxton's dog:Abby's dog)

=> (Braxton's dog:Abby's dog) = 4.5:1.5

<u>Now, put them into fractions.</u>

=> 4.5:1.5 = 4.5/1.5 = 3

We can conclude that Braxton's dog eats 3 times more food.

4 0

2 years ago

Read 2 more answers

You estimated the average rental cost of a 2 bedroom apartment in Denton. A random sample of 16 apartments was taken. The sample

Zigmanuir [339]

Answer:

The new sample size required in order to have the same confidence 95% and reduce the margin of erro to $60 is:

n=28

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma=160)$

And the distribution for $\bar X$ is:

$\bar X \sim N(\mu, \frac{160}{\sqrt{n}})$

We know that the margin of error for a confidence interval is given by:

$Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The next step would be find the value of $\z_{\alpha/2}$ , $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$

Using the normal standard table, excel or a calculator we see that:

$z_{\alpha/2}=\pm 1.96$

If we solve for n from formula (1) we got:

$\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}$

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

And we have everything to replace into the formula:

$n=(\frac{1.96(160)}{78.4})^2 =16$

And this value agrees with the sample size given.

For the case of the problem we ar einterested on Me= $60, and we need to find the new sample size required to mantain the confidence level at 95%. We know that n is given by this formula:

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

And now we can replace the new value of Me and see what we got, like this:

$n=(\frac{1.96*160}{60})^2 =27.32$

And if we round up the answer we see that the value of n to ensure the margin of error required $Me=\pm 60$ $ is n=28.

5 0

2 years ago

Can anyone help me with the odd numbers on my algebra 1 homework?

WINSTONCH [101]

y =x+10

y =6x+30

substitute x+10 into the 2nd equation anywhere you see y

x+10 = 6x+30

subtract x from each side

x-x+10 = 6x-x+30

10 = 5x+30

subtract 30 from each side

10-30=5x+30-30

-20 = 5x

divide by 5 on each side

-20/5 =5x/5

-4=x

now solve for y

y=x+10

y = -4 +10

y=6

Answer: x=-4

y=6

or (-4,6)

3. y = -3x-6

6x+5y=-30

6x+5(-3x-6) =-30

5x-15x-30=-30

-20x-30=-30

-20x=0

x=0

y = -3x-6

y=-6

6 0

2 years ago

Cecil had 6 ice cubes. He put 1 ice cube in each glass. In how many glasses did Cecil put ice cubes?

Kamila [148]

He only puts 1 in each glass and he has six. The answer is 6.

7 0

2 years ago

Read 2 more answers