Answer:
Look at the pictures. On the 1 are compounds A and B. Compound c from b is on the 2nd image. Compound D is on 3rd image. Compound E is the same for compound C.
Explanation:
So for compound A sodium acetylide substitutes nucleophilicaly one Br on 1,12-dibromododecane. Then to obtain compound B sodium amide eliminates another Br. So for acetylene and alkene groups ozonolysis works the same way and we obtain diacid. Lyndlar catalyst works only on alkynes and make cis-alkenes from them. but we have a terminal alkyne for wich no isomers may occur. Pt reduction provides alkanes from both alenes and akynes. And sodium ammonia reduction works only on alkynes to provide trans-alkenes but, as I've said, isomers are not our case. So compounds E and C are the same and undergo same reaction with ozone.
6 atoms of Cobalt.
4 atoms to Phosphate (PO4).
6 atoms to sodium.
6 atoms to Chlorine.
The coefficient is one factor that tells you how many atoms go to each atom/element, however, the subscript also influences this.
If the compound has parenthesis, then the subscript within the parenthesis remains untouched and does not affect the atoms.
Basically, to calculate the atoms is multiply the coefficient (number in front of the atom) by the subscript attached to the atom. If it's a compound such as Co3PO4, then make sure the coefficient affects the second atom as well.
Hope this helps!
Answer:
2.89
Explanation:
pH=-log(H+)
- Hope that helps! Please let me know if you need further explanation.
I believe it’s conductivity
Yeah, a lot faster than sound.