Answer: The equilibrium concentration of hydrogen gas is 0.0269 M
Explanation:
The chemical reaction follows the equation:

At t = 0 0.044M 0.044M 0.177M
At
(0.044-x)M (0.044-x)M (0.177+x)M
The expression for
for the given reaction follows:
![K_c=\frac{[HI]^2}{[H_2]\times [I_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5Ctimes%20%5BI_2%5D%7D)
We are given:

Putting values in above equation, we get:


Hence, the equilibrium concentration of hydrogen gas is (0.044-x) M =(0.044-0.0171) M= 0.0269 M
Sodium oxide and carbon dioxide
Explanation:
When sodium carbonate decomposes sodium oxide and carbon dioxide is produced:
Na₂CO₃ → Na₂O + CO₂
- This kind of reaction is known as decomposition reaction.
- In a decomposition reaction,
- In this kind of reaction, two or more products form from a single reactant.
- The breakdown of a compound into its component individual elements or other compounds falls into this reaction category.
Learn more:
Thermal decomposition brainly.com/question/11181911
#learnwithBrainly
A function describing the location and wave-like behavior of an electron in an atom.
Answer:
116.5 g of SO₂ are formed
Explanation:
The reaction is:
S₈(g) + 8O₂(g) → 8SO₂ (g)
Let's identify the moles of sulfur vapor, by the Ideal Gases Law
We convert the 921.4°C to Absolute T° → 921.4°C + 273 = 1194.4 K
5.87 atm . 3.8L = n . 0.082 L.atm/mol.K . 1194.4K
(5.87 atm . 3.8L) / (0.082 L.atm/mol.K . 1194.4K) = n → 0.228 moles of S₈
Ratio is 1:8, 1 mol of sulfur vapor can produce 8 moles of dioxide
Then, 0.228 moles of S₈ must produce (0.228 . 8) /1 = 1.82 moles
We convert the moles to g → 1.82 moles . 64.06 g /1mol = 116.5 g