Calculate the change in internal energy of the following system: A 100.0-g bar of gold is heated from 25∘C to 50∘C during which
1 answer:
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For the 1st order reactions,rate constant (k) is mathematically expressed as
k =
where, t = time
Co = initial conc. of reactant
Ct = conc. of reactant after time 't'
Given: k = <span>2.20 × 10^-5 s-1, t = 2 hours = 7200 s
Therefore, we have
</span>2.20 × 10^-5 =
∴
= 0.06877
∴,
= 1.1716
∴, Ct = 85.35%
Thus, <span>85.35 % of the initial amount of SO2Cl2 will remain after 2.00 hours.</span>
k =
where, t = time
Co = initial conc. of reactant
Ct = conc. of reactant after time 't'
Given: k = <span>2.20 × 10^-5 s-1, t = 2 hours = 7200 s
Therefore, we have
</span>2.20 × 10^-5 =
∴
∴,
∴, Ct = 85.35%
Thus, <span>85.35 % of the initial amount of SO2Cl2 will remain after 2.00 hours.</span>
Answer:
Molar absorptivity or molar extinction co-effecient = 2120.14 cm⁻¹M⁻¹
Explanation:
First convert Concentration from ppm inM or mol/l
⇒ Molar mass of KMnO₄ = 158.03 g
⇒ 4.48 ppm = 4.48 mg/l = 4.48 x 10⁻³ g/l
⇒ Molarity = = 2.83 x 10⁻⁵ molar
Absorbance (A) = - log(T) ( T = % transmittance)
= - log(0.859)
= 0.06
According to Lambert Beer's law
ε =
or, ε =
or, ε = 2120.14 cm⁻¹M⁻¹
Where
ε = Molar absorptivity
A = absorbance
C = Molar concentration of KMnO₄ solution
l = length