Question

The amount of heat needed to raise 25 g of a substance by 15°C is 293 J. What is the specific heat of the substance? Use the equation C = q/mΔT.
a.) 0.13 J/g-°C

b.) 0.20 J/g-°C

c.) 0.78 J/g-°C

d.) 0.46 J/g-°C

Answer 1

It is so simple and direct substitution in the formula of :
C= Q/ m ΔT
when C is specific heat constant
and Q is heat energy of joul 
and m is the mass
and ΔT is the change in temperature
and when we have Q = 293 J & m = 25 g & ΔT = 15 °C so by substitution:
∴C = 293/(25*15)
      = 0.78 J/g-°C 
∴ 0.78 J/g-°C is the correct answer