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grin007 [14]
3 years ago
6

The amount of heat needed to raise 25 g of a substance by 15°C is 293 J. What is the specific heat of the substance? Use the equ

ation C = q/mΔT.
a.) 0.13 J/g-°C

b.) 0.20 J/g-°C

c.) 0.78 J/g-°C

d.) 0.46 J/g-°C
Chemistry
1 answer:
balandron [24]3 years ago
3 0
It is so simple and direct substitution in the formula of :
C= Q/ m ΔT
when C is specific heat constant
and Q is heat energy of joul 
and m is the mass
and ΔT is the change in temperature
and when we have Q = 293 J & m = 25 g & ΔT = 15 °C so by substitution:
∴C = 293/(25*15)
      = 0.78 J/g-°C 
∴ 0.78 J/g-°C is the correct answer

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We have \displaystyle \frac{dV}{dt} = \frac{10 \ cm^3}{sec} and we want to find \displaystyle \frac{dh}{dt} \Biggr | _{h\ =\ 6}= \ ? when the height is 2 cm.

We can see in our equation for the volume of a cone that we have three variables: V, r, and h.

Since we only have dV/dt and dh/dt, we can rewrite the equation in terms of h only.

We are given that the height of the cone is 1/5 the radius at any given time, 1/5r, so we can write this as r = 5h.

Plug this value for r into the volume formula:

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Differentiate this equation with respect to time t.

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Plug known values into the equation and solve for dh/dt.

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Divide both sides by 100π to solve for dh/dt.

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The height of the cone is increasing at a rate of 1/10π cm per second.

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