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Vladimir79 [104]
3 years ago
10

Please help!-- 20 pts!

Chemistry
1 answer:
ratelena [41]3 years ago
5 0

Answer:

Both oil and gasoline molecules are nonpolar, while water is polar. Nonpolar solvents have a tendency to dissolve other nonpolar molecules.

Explanation:

Molecules may be categorized as "polar" or "nonpolar" according to <em>difference in the atom's electronegativity.</em>

<u>Water is polar</u> because it consists of two types of atoms that<em> do not cancel out each other.</em> It is made of two atoms of Hydrogen and only one atom of Oxygen. This makes the Oxygen<u> partially negative</u> and the Hydrogen <u>partially positive.</u> This allows them to readily bond with other polar molecules like sugar. However, it cannot mix freely with oil and gasoline because<em> both of these are nonpolar. </em>Nonpolar molecules do not have much difference when it comes to their atoms' electronegativity. <em>Therefore, they have the tendency to dissolve molecules which are nonpolar as well. </em>This explains why oil molecules can mix freely with gasoline.

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Solid, Liquid, Gas.

Explanation:

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Why did mendeleev switch iodine and tellurium?
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An example would be iodine has a lower relative atomic mass than tellurium, so it should come before tellurium in Mendeleev's table. In order to get iodine in the same group as the other elements with similar properties such as fluorine, chlorine, and bromine, he had to put it after tellurium, which broke his own rules.
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3 years ago
Really need help with this! Chemistry
Westkost [7]

Answer:

a) 0,5

Explanation:

If x=6 and y=2, then (2x-4y)/(x+y)=(2*6-4*2)/(6+2)=(12-8)/8=4/8= 0,5

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2 years ago
The physical matter of which living or nonliving things are composed is called a ___
kolezko [41]

Answer:

Substance

Explanation:

Any physical matter despite of living or non living things are composed by a set of molecules or atoms commonly known as substance

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3 0
2 years ago
For parts a &amp; b below, derive only the initial value problem set up.
Otrada [13]

Answer:

Explanation:

From the given information:

Let y(t) be the amount of sugar in tank A at any time.

Then, the rate of change of sugar in the tank is given by:

\dfrac{dy}{dt}= (rate \ in ) - ( rate \ out )

The rate of the sugar coming into the tank is 0

\text{rate of sugar going out }= \dfrac{y(t) \ pound}{100}\times \dfrac{1 }{min} \\ \\ = \dfrac{y}{100} \ pound/min

So; \\ \\ \\ \dfrac{dy}{dt} = 0 - \dfrac{y}{100}  \\ \\ \implies \dfrac{dy}{y }= -\dfrac{dt}{100 } \\ \\ \implies dx|y| = -\dfrac{t}{100}+C  \\ \\  \implies e*{In|y|}= e^{-\dfrac{t}{100}+C} \\ \\ \implies y = Ce^{-\dfrac{t}{100}}

Initial amount of sugar = 25 Pounds

Now; y(0) = 25

25 = Ce⁰

C = 25

So;  y(t) = 25 e^{-\dfrac{t}{100}

Thus, the amount of sugar at any time t = \mathbf{25 e^{^{-\dfrac{t}{100}}}}

B) For tank B :

\dfrac{dy}{dt}= 1 - \dfrac{y}{50 } \\ \\ \dfrac{dy}{dt}= \dfrac{50-y}{50} \\ \\  \dfrac{dy}{50-y }= \dfrac{dt}{50}

8 0
3 years ago
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