The correct chemical formula for the product of the reaction when beryllium and fluorine combine is BF₂.
The valence electron of an atom determines how an atom goes into bonding.
Beryllium(Be) has 4 electron and has 2 valence electron. To fulfil the octet rule, it can easily give out this 2 electron during bonding.
Fluorine(F) has 9 electrons and 7 valency electrons. To fulfil the octet rule, it readily accepts a single electron.
The correct chemical formula for the product of the reaction when beryllium and fluorine combine is BF₂.
This means 1 atom of beryllium combines with 2 atoms of fluorine to form beryllium fluoride. The beryllium give its 2 valency electrons to the 2 atoms of fluorine. The 2 atoms of fluorine will now have a valency electron of 8 each. The octet rule has been fulfilled at this point.
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Answer:
Part A: 27.8 L; Part B: 0.500 mol
Explanation:
Part A
For an ideal gas, we can use the equation:
PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
In the beggining:
P*48.0 = 1.90*RT
P/RT = 1.90/48.0
P/RT = 0.03958
For constants pressure and temperature, after 0.800 mol of gas leaks out: n = 1.90 - 0.800 = 1.10 mol
PV = 1.10*R*T
P/RT = 1.10/V
0.03958 = 1.10/V
V = 1.10/0.03958
V = 27.8 L
Part B
In the beginning
PV = nRT
P*70.0 = 2.00*RT
P/RT = 2.00/70.0
P/RT = 0.02857
After the gas leaked out:
PV = nRT
P*17.5 = nRT
P/RT = n/17.5
0.02857 = n/17.5
n = 0.500 mol
273.15 K (0 °C, 32 °F) and an absolute pressure of 101.325 kPa (14.7 psi, 1.00 atm, 1.01325 bar).
Answer:
Energy
Explanation:
Energy can simply be defined as the ability to do work. It is a measure of the amount of work a body or object can do. The more the work a body is able to accomplish, the more the energy it posses. The unit of energy is always expressed in joules.
Mass is the amount of matter in a substance.
Velocity is rate of change of displacement with time.
a. The calories increase by 9:00 whenever the running speed goes up by two. so so if a dog were running at 10 km/h it would be 54 calories burnt
b. they are multiplied by 9