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3 years ago

When hydrogen is burned as a fuel, the primary waste product produced is ________?

Chemistry

2 answers:

Lana71 [14]3 years ago

5 0

Explanation:

A combustion reaction is defined as the one which when reacts with oxygen atom results in the formation of carbon dioxide and water.

As most of the fuels are hydrocarbons hence, they also produce carbon dioxide and water upon combustion.

And, when hydrogen is burned as a fuel then the reaction is as follows.

$2H_{2} + O_{2} \rightarrow 2H_{2}O$

Thus, we can conclude that when hydrogen is burned as a fuel, the primary waste product produced is $H_{2}O$ .

lora16 [44]3 years ago

3 0

2H2 +O2 ----> H2O
The primary product is water.

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True or False: when steam condenses into a liquid, heat is given off to the environment.

jolli1 [7]

Answer:

true.

Explanation:

3 0

4 years ago

For each of the following nuclei, determine the binding energy per nucleon (in MeV). (For all masses, keep six places beyond the

garik1379 [7]

Answer: (a) BE = 1.112 MeV

(b) BE = 7.074 MeV

(d) BE = 8.112 MeV

Explanation: Binding energy per nucleon is the average energy necessary to remove a proton or a neutron from the nucleus of an atom. It is mathematically defined as:

$BE = \frac{\Delta m.c^{2}}{A}$

Where

Δm is a difference in mass known as mass defect

A is atomic mass of an atom.

Mass Defect is determined by:

$\Delta m =Zm_{p}+(A-Z)m_{n} - m_{nuc}$

where:

Z is atomic number

$m_{p}$ is mass of proton

$m_{n}$ is mass of neutron

$m_{nuc}$ is mass of the nucleus

Mass of proton is 1.007825u.

Mass of neutron is 1.008665u.

The unit u is equal to 931.5MeV/c².

(a) 2H(deuterion): Given: Z = 1; A = 2; $m_{nuc}$ = 2.014102u

$\Delta m =1(1.007825)+1(1.008665) -2.014102$

$\Delta m =0.002388u$

$BE = \frac{0.002388.c^{2}}{2}.931.5\frac{MeV}{c^{2}}$

BE = 1.112MeV

(b) 4He (Helium): Given: Z = 2; A = 4; $m_{nuc}$ = 4.002603

$\Delta m =2(1.007825)+2(1.008665) -4.002603$

$\Delta m =0.030377u$

$BE = \frac{0.030377.c^{2}}{4}.931.5\frac{MeV}{c^{2}}$

BE = 7.074MeV

$\Delta m =8(1.007825)+10(1.008665) -17.999160$

$\Delta m =0.15009u$

$BE = \frac{0.15009.c^{2}}{18}.931.5\frac{MeV}{c^{2}}$

BE = 7.767MeV

(d) 23Na (Sodium): Given: Z = 11; A = 23; $m_{nuc}$ = 22.989767

$\Delta m =11(1.007825)+12(1.008665) -22.989767$

$\Delta m =0.200288u$

$BE = \frac{0.200288.c^{2}}{23}.931.5\frac{MeV}{c^{2}}$

BE = 8.112MeV

3 0

3 years ago

What particles are found in the nucleus of an atom?

Nana76 [90]

It’s a neutrons and electrons

6 0

4 years ago

Ionic compound of GaTe

kow [346]

Answer:

Gallium(II) telluride

Explanation:

3 0

3 years ago

Type the correct answer in each box.

krok68 [10]

Answer:

2KI → 2K + I₂

Explanation:

(not my definition, but form a trustworthy source)

The definition of a decomposition reaction is:

a chemical reaction in which one reactant breaks down into two or more products.

In this case, potassium iodide will decompose into potassium and iodine.

2KI → 2K + 2I

2 Potassium and 2 Iodine on both sides, so equation is balanced.

Or, it can be written as 2KI → 2K + I₂

8 0

2 years ago