<h3>
The dimensions of the given rectangular box are:</h3><h3>
L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>
Step-by-step explanation:
Let us assume that the dimension of the square base = S x S
Let us assume the height of the rectangular base = H
So, the total area of the open rectangular box
= Area of the base + 4 x ( Area of the adjacent faces)
= S x S + 4 ( S x H) = S² + 4 SH ..... (1)
Also, Area of the box = S x S x H = S²H
⇒ S²H = 2000
Substituting the value of H in (1), we get:
Now, to minimize the area put :
Putting the value of S = 15.874 cm in the value of H , we get:
Hence, the dimensions of the given rectangular box are:
L = 15.874 cm
B = 15.874 cm
H = 7.8937 cm
Answer:
x = - 2, x = - 
Step-by-step explanation:
Given
5x² + 1 = - 13x - 5 ( add 13x - 5 to both sides )
5x² + 13x + 6 = 0
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term
product = 5 × 6 = 30 and sum = 13
The factors are 10 and 3
Use these factors to split the x- term
5x² + 10x + 3x + 6 = 0 ( factor the first/second and third/fourth terms )
5x(x + 2) + 3(x + 2) = 0 ← factor out (x + 2) from each term
(x + 2)(5x + 3) = 0
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
5x + 3 = 0 ⇒ 5x = - 3 ⇒ x = -
Answer:
<u>y = -3x + 8</u>
Step-by-step explanation:
<u>Given :-</u>
Point on line = (5, -7)
Slope (m) = -3
<u>To find :-</u>
Equation of line
<u>Solving :-</u>
Using point-slope form of equation,
y - y₁ = m(x - x₁)
y + 7 = -3(x - 5)
y + 7 = -3x + 15
<u>Solution :-</u>
<u>y = -3x + 8</u>
It’s going to be 1/2(6^2 + 4) = 20
250 bc if the original weight goes down 50 lbs for the male tiger it must apply for the female as well
