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ivolga24 [154]
2 years ago
8

Please please help me with this question please

Mathematics
2 answers:
Cerrena [4.2K]2 years ago
8 0
Plug in the value
(2.5 + 4)^2
Remember that parenthesis should go first: 2.5 + 4 = 6.5
Now square that. (6.5)^2 = 42.25
The solution is 42.25
Pachacha [2.7K]2 years ago
5 0

Step-by-step explanation:

(2.5 + 4)^2

(2.5 + 4)(2.5 + 4)

6.5 x 6.5

42.25

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Step-by-step explanation:

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3 years ago
What's (2x) ^3 in expanded notation form?
inessss [21]

Answer:

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Step-by-step explanation:

{(2x)}^{3}

= <em><u>2x × 2x × 2x (In expanded notation form) (Ans)</u></em>

5 0
3 years ago
Read 2 more answers
What would y be if 8x-6y=36
kondor19780726 [428]

Answer:

\quad y=-\frac{2\left(-2x+9\right)}{3}

Step-by-step explanation:

1. Subtract 8x from both sides:

8x-6y-8x=36-8x

2. Simplify:

-6y=36-8x

3. Divide both sides by -6

\frac{-6y}{-6}=\frac{36}{-6}-\frac{8x}{-6}

4. Simplify to get answer

8 0
3 years ago
The formula for wind chill C (in degrees Fahrenheit) is given by C = 35.74 + 0.6215T - 35.75v^0.16 + 0.4275Tv^0.16 where v is th
Diano4ka-milaya [45]

Answer:

dC = 2.44

Relative error = 19%

Step-by-step explanation:

C = 35.74 + 0.6215*T - 35.75*v^(0.16) + 0.4275*T*v^(0.16)

Δv = 3 ; ΔT = 1 , v = 23, T = 8

Use differential Calculus

dC = Cv.dv + Ct.dt

Cv = dC/dv = -5.72*v^(-0.84) + 0.0684*T*v^(-0.84)\\Ct = dC/dT = 0.6215 + 0.4275*v^(0.16)\\dC = modulus (Cv.dv) + modulus (CT.dT)\\dC = (-5.72*v^(-0.84) + 0.0684*T*v^(-0.84))* 3 + (0.6215 + 0.4275*v^(0.16))*1\\dC = 2.44

Relative Error

dC / C @(T = 8, v=23)  * 100 = 19 %

8 0
3 years ago
For each triangle, find the missing side length to the nearest tenth. :
Lana71 [14]
We can use trigonometry.  The cosine of 15 will be the side adjacent to the 15-degree side (the one we are looking for) divided by 20, the hypotenuse.  As cos(15) is about .966, we get 19.32 as the side we are looking for.
3 0
3 years ago
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