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ira [324]
2 years ago
15

I will mark brainliest when allowed!

Mathematics
2 answers:
Andru [333]2 years ago
7 0
The slope is -1/5 . When you have two points, the slope of the line through both of them is (difference in y) ÷ (difference in x) . You did it the other way around, and got the reciprocal. ( 1 / slope )
Sergeeva-Olga [200]2 years ago
6 0

Answer:

-0.2

Step-by-step explanation:

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An electric motor makes 3,000 revolutions per minutes. How many degrees does it rotate in one second?
GrogVix [38]
Maybe like 5 minutes because of how much it is turning in a minimum amount of time

6 0
4 years ago
Complete the proof for me please, I need help
Naya [18.7K]

Answer:

See explanation for answers

Step-by-step explanation:

Reason 1) Given from the problem statement(because it says that B is the midpoint of AC)

Reason 2) Because B is the midpoint of AC

Reason 3) Given frome the problem statement(because it says that AB/cong CD)

Reason 4) Because two lines congruent to each other have the same length

Reason 5(You didn't explain well)) BC=AB=CD, so BC=CD(Specific reason: Transitivity of equality)

And we're done!

4 0
3 years ago
What is the common ratio of 2, 10/3, 50/9
mojhsa [17]

The common ratio of 2, 10/3, 50/9 is \frac{10}{6}

<u>Solution:</u>

Given, series of elements are 2, \frac{10}{3}, \frac{50}{9}

We have to find the common ratio of the above given series.

We know that, common ratio of an G.P is division of any number in that series with the previous number of the series.

So, now take \frac{10}{3} and 2

\text { Then, common ratio }=\frac{\frac{10}{3}}{2}

\begin{array}{l}{\text { Common ratio }=\frac{10}{3} \times \frac{1}{2}} \\\\ {\text { Common ratio }=\frac{10}{3 \times 2}=\frac{10}{6}}\end{array}

Hence, the common ratio of the given series is \frac{10}{6}

6 0
3 years ago
-8 + 5x - 2 = 20 solve
vaieri [72.5K]

Combining like terms on the left-hand side gives us 5x-10=20. Adding 10 to both sides gives 5x=30, and dividing both sides by 5 gives our answer of \boxed{x=6}.

3 0
3 years ago
Can someone please help me with this problem asap
Kitty [74]
Where is the problem at? give me the url

6 0
3 years ago
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