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3 years ago

Help please and explain how to get the answerm

Mathematics

1 answer:

OverLord2011 [107]3 years ago

7 0

Answer:

147 degrees

Step-by-step explanation:

all the angles of a triangle add up to 180 degrees. so, you must perform the operation 180-(83+64) which equals 33. this is the angle supplementary to angle 1. to find angle 1, you must subtract 180 and 33 since supplementary angles add up to 180 degrees. this is equal to 147 degrees.

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On a number line what is the distance between -12 and 20 ??

KIM [24]

Answer: Step-by-step explanation:

In order to answer this question you will need to find 2 distances and then add them to each other.

Begin at -29. How far will you have to move to the right 29 in order to get to 0?

Now how far will you have to more to get from 0 to 100?

Draw an open number line to help you.

_____________________________________________________

-29 0 100

Your first distance is 29. Your second distance is 100. The total distance is 129.

3 0

4 years ago

For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

5 0

3 years ago

How much would $500 invested at 9% interest compounded annually be

dalvyx [7]

Answer:

$705.79.

Step-by-step explanation:

The formula is

Amount = P(1 + r/100) ^ t so

Amount = 500 (1 + 9/100)^4

= $705.79.

8 0

4 years ago

Read 2 more answers

EASY 14 POINTS, PLEASE HELP ASAP.

jenyasd209 [6]

Well really it would have to depend on the flashlight. Is it an led bulb or a regular bulb?

5 0

3 years ago

Read 2 more answers

What is the domain and range of <br> f(x)=2x^2+6x+2

lbvjy [14]

As is the case for any polynomial, the domain of this one is (-infinity, +infinity).

To find the range, we need to determine the minimum value that f(x) can have. The coefficients here are a=2, b=6 and c = 2,

The x-coordinate of the vertex is x = -b/(2a), which here is x = -6/4 = -3/2.

Evaluate the function at x = 3/2 to find the y-coordinate of the vertex, which is also the smallest value the function can take on. That happens to be y = -5/2, so the range is [-5/2, infinity).

3 0

3 years ago