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Liono4ka [1.6K]

4 years ago

9

What is (5.2 × 102) × (1.2 × 104)?

1 answer:

Maksim231197 [3]4 years ago

7 0

<span> (5.2 × 10^2) × (1.2 × 10^4)
=</span><span> (5.2 × 1.2) × 10^6
= 6.24 x 10^6

answer </span><span>D.
6.24 × 10^6</span>

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21, it says it right in the name.

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4 years ago

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Solve for b a=b-4/c

Agata [3.3K]

Answer:

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3 years ago

What are the solutions to the following system?<br> -2x+y=-5<br> y --3x²+5<br> L

seraphim [82]

The problem seems confusing is it supposed to say y=?

3 0

4 years ago

Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.

Lelechka [254]

Answer:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}} = 32$

Step-by-step explanation:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}$

Solving using exponent rule: $a^{-m}=\frac{1}{a^m}$

$\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32$

So, $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4}$

Using the exponent rule: $a^m.a^n=a^{m+n}$

We have:

$2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}$

We also know that: $a^{-m}=\frac{1}{a^m}$

Using this rule:

$2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}$

So, $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2$

Solving:

$(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}$

So, $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}}$

We know that: $a^{-m}=\frac{1}{a^m}$

$\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32$

So, $\frac{2}{2^{-4}} = 32$

3 0

3 years ago

The value of y is inversely proportional to the value of x. When y=42, x=6.

NARA [144]

Because $x$ and $y$ are inversely proportional, there is some constant $k$ such that

$xy=k$

Given that $y=42$ and $x=6$ , we have

$k=6\times42=252$

So when $x=9$ , you have

$9y=252\implies y=\dfrac{252}9=28$

4 0

3 years ago