Mr. Hayes has Ill straw bundles to use for bedding in his horse stalls. What is the
1 answer:
We have been given that Mr. Hayes has 111 straw bundles to use for bedding in his horse stalls. We are asked to find the greatest number of bundles that he can fill if each stall holds exactly 4 bundles of straw.
To solve our given problem, we will divide 111 by 4.
Since 0.75 is not an integer, so Mr. Hayes cannot fill 0.75 of a stall. Therefore, the greatest possible number of stalls will be 27.
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Answer:
- (2, 3.5) or (2, 3)
Step-by-step explanation:
<em>See attached.</em>
The intersection of the lines is the solution.
<u>Approximate values of the coordinates is:</u>
- (2, 3.5) or (2, 3) if integer values are required
Answer:
The value of b is, 8
Step-by-step explanation:
To determine the value of b:
Given:
....[1]
Since, 0x6A represents the hexadecimal form.
To convert this hexadecimal form into decimal form:
⇒(decimal form)
Now we have to convert this decimal form into octal
8 | 106
8 | 13 | 2
| 1 | 5
1
Then, the octal form we get,
Substitute this in [1] we have;
On comparing both sides we have;
b = 8
Therefore, the value of b is, 8