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Lera25 [3.4K]
3 years ago
11

Solve. *25 points* 1/2 divided by 2/3 =?

Mathematics
1 answer:
Colt1911 [192]3 years ago
7 0

Answer:

The answer is 3/4

Step-by-step explanation:

When you divide two fractions, such as 1/2 ÷ 2/3, you have to flip the second fraction and then you simply multiply the numerators with each other and the denominator with each other.

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10 kids are randomly grouped into an A team with five kids and a B team with five kids. Each grouping is equally likely. (a) Wha
nikitadnepr [17]

Answer:

I think B is 1/5. I think C is 1/2.

4 0
3 years ago
Read 2 more answers
Chase consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Chase's body
PIT_PIT [208]

Answer:

(a) The 5-hour decay factor is 0.5042.

(b) The 1-hour decay factor is 0.8720.

(c) The amount of caffeine in Chase's body 2.39 hours after consuming the drink is 149.112 mg.

Step-by-step explanation:

The amount of caffeine in Chase's body decreases exponentially.

The 10-hour decay factor for the number of mg of caffeine is 0.2542.

The 1-hour decay factor is:

1-hour\ decay\ factor=(0.2542)^{1/10}=0.8720

(a)

Compute the 5-hour decay factor as follows:

5-hour\ decay\ factor=(0.8720)^{5}\\=0.504176\\\approx0.5042

Thus, the 5-hour decay factor is 0.5042.

(b)

The 1-hour decay factor is:

1-hour\ decay\ factor=(0.2542)^{1/10}=0.8720

Thus, the 1-hour decay factor is 0.8720.

(c)

The equation to compute the amount of caffeine in Chase's body is:

A = Initial amount × (0.8720)<em>ⁿ</em>

It is provided that initially Chase had 171 mg of caffeine, 1.39 hours after consuming the drink.

Compute the amount of caffeine in Chase's body 2.39 hours after consuming the drink as follows:

A = Initial\ amount \times (0.8720)^{2.39} \\=[Initial\ amount \times (0.8720)^{1.39}] \times(0.8720)\\=171\times 0.8720\\=149.112

Thus, the amount of caffeine in Chase's body 2.39 hours after consuming the drink is 149.112 mg.

4 0
3 years ago
7 (8.02) need answer asap
timama [110]
Both groups are similar.
7 0
3 years ago
Determine the unknown angle measures, to the nearest degree, in the diagram provided.
serg [7]

Answer:

a is <u>5</u><u>3</u><u>.</u><u>8</u><u>°</u><u>,</u> and b is <u>3</u><u>6</u><u>.</u><u>2</u><u>°</u>

Step-by-step explanation:

Using sine trig rule:

{ \boxed{ \bf{ \sin(b) =  \frac{opposite}{hypotenuse}  }}}

{ \tt{ \sin(b) =  \frac{78}{132}  }} \\  \\ { \tt{b =  { \sin }^{ - 1}( \frac{78}{132} ) }} \\  \\ { \tt{b = 36.2 \degree}}

Summation of angles of triangle:

{ \tt{a + b + 90 \degree = 180 \degree}} \\ { \tt{a + 36.2 \degree + 90 \degree = 180 \degree}} \\ { \tt{a = (180 - 36.2 - 90) \degree}} \\ { \tt{a = 53.8 \degree}}

7 0
3 years ago
A recent gasoline survey said that the national average price of gasoline was $1.298 a gallon. It was felt that gasoline price i
slava [35]

Answer:

<em>alternative hypothesis : H₁ :</em>

<em>Recent  Gasoline surveys felt that gasoline price in Texas was significantly lower than the national average</em>

<em>Alternative Hypothesis : H₁: μ < $1.298 a gallon</em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given A recent gasoline survey said that the national average price of gasoline was $1.298 a gallon

<em>Population average μ= $1.298 a gallon</em>

<em>sample size 'n' = 37</em>

<em>Sample mean (x⁻) = $1.192 a gallon </em>

<em>Sample standard deviation 'S' = $0.0436</em>

<em>Null hypothesis :H₀ : μ =  $1.298 a gallon</em>

<em>Alternative Hypothesis : μ < $1.298 a gallon</em>

<em>Degrees of freedom : ν = n-1= 37-1=36</em>

<em>t₀.₀₂₅ = 1.688</em>

<em>Test statistic </em>

<em>                        </em>t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }<em></em>

<em>                        </em>t = \frac{1.192-1.298 }{\frac{0.0436}{\sqrt{37} } }<em></em>

<em>                      t =  -14.8044</em>

<em>|t| = |-14.8044| > 1.688</em>

<em>Null hypothesis is rejected </em>

<em>Alternative hypothesis is accepted </em>

<em>Recent  Gasoline surveys felt that gasoline price in Texas was significantly lower than the national average</em>

6 0
3 years ago
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