Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
You didn’t add any pictures so how could i help you with this?
Answer: look at the picture
Step-by-step explanation: Hope this help :D, Can I have a Brainliest I really needed it please
First plug in g(x) into f(x)
F((g(x))=2(2x+3)
And now you plug in -8
F(g(-8))=2(-16+3)
F(g(-8))=2(-13)
F(g(-8))=-26
Answer:
it's 2 because it's the smallest number
